17 mol O2 10. What is the percentage yield of ammonia when 14.0 g of N2 gas reacts with 5.0 g of H₂ to produce 12.0 g of NH3? Molecular weights: N₂- 28.02 g/mol, H₂= 2.02 g/mol, NH3 17.04 g/mol N₂ + H₂ → NH3 A) 63.2 % C) 70.5% B) 42.9% D) 55.8 %

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10. What is the percentage yield of ammonia when 14.0 g of N₂ gas reacts with 5.0 g of H₂ to produce 12.0 g of NH₃?

Molecular weights:
- N₂ = 28.02 g/mol
- H₂ = 2.02 g/mol
- NH₃ = 17.04 g/mol

\[ \text{Chemical Equation:} \]
\[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \]

Options:
A) 63.2%
B) 42.9%
C) 70.5%
D) 55.8%

The answer 70.5% is circled.
Transcribed Image Text:10. What is the percentage yield of ammonia when 14.0 g of N₂ gas reacts with 5.0 g of H₂ to produce 12.0 g of NH₃? Molecular weights: - N₂ = 28.02 g/mol - H₂ = 2.02 g/mol - NH₃ = 17.04 g/mol \[ \text{Chemical Equation:} \] \[ \text{N}_2 + 3\text{H}_2 \rightarrow 2\text{NH}_3 \] Options: A) 63.2% B) 42.9% C) 70.5% D) 55.8% The answer 70.5% is circled.
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