Question 16 of 24 Submit How many grams of oxygen gas are produced when 2.43 x 10-ªg of KCIo, are completely reacted according to the following chemical equation: 2 KCIO (s) → 2 KCI(s) + 3 02(g) STARTING AMOUNT ADD FACTOR ANSWER RESET
Question 16 of 24 Submit How many grams of oxygen gas are produced when 2.43 x 10-ªg of KCIo, are completely reacted according to the following chemical equation: 2 KCIO (s) → 2 KCI(s) + 3 02(g) STARTING AMOUNT ADD FACTOR ANSWER RESET
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 116SCQ: Calculate rH for the reaction 2 C(s) + 3 H2(g) + O2(g) C2H5OH() given the information below. C(s)...
Related questions
Question
![**Question 16 of 24**
**Chemical Reaction Problem:**
How many grams of oxygen gas are produced when \(2.43 \times 10^{-4}\) g of KClO\(_3\) are completely reacted according to the following chemical equation:
\[ 2 \text{ KClO}_3(s) \rightarrow 2 \text{ KCl}(s) + 3 \text{ O}_2(g) \]
**Calculation Interface:**
- **Starting Amount Box:** This section requires input for the starting amount of the substance in question.
- **Equation Structure:** The interface employs multiplication and division to convert between units.
**Factors Available for Calculation:**
- \(1\)
- \(32.00\)
- \(1.90 \times 10^{-4}\)
- \(74.55\)
- \(1.98 \times 10^{-6}\)
- \(2.43 \times 10^{-4}\)
- \(2.97 \times 10^{-6}\)
**Conversion and Calculation Options:**
- **Grams to Moles and Vice Versa:**
- \(9.52 \times 10^{-5}\) g KClO\(_3\)
- \(2\) mol KClO\(_3\)
- \(3\) mol KCl
- \(5.95 \times 10^{-6}\) mol O\(_2\)
- \(6.022 \times 10^{23}\) g O\(_2\)
- \(122.55\) g KCl
**Functional Buttons:**
- **Add Factor:** Allows for the inclusion of an additional conversion or reaction factor.
- **Answer Box:** Entry for the calculated result in the desired unit.
- **Reset Button:** Clears current calculations to restart the problem.
**Resource Note:**
Access additional resources at the bottom of the interface for further exploration and learning.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7127fdb-1b09-43df-9c21-7fe264d46fd8%2F8a4f1335-277c-4bc7-ae21-3164d5fd9f65%2Fwec2uzi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 16 of 24**
**Chemical Reaction Problem:**
How many grams of oxygen gas are produced when \(2.43 \times 10^{-4}\) g of KClO\(_3\) are completely reacted according to the following chemical equation:
\[ 2 \text{ KClO}_3(s) \rightarrow 2 \text{ KCl}(s) + 3 \text{ O}_2(g) \]
**Calculation Interface:**
- **Starting Amount Box:** This section requires input for the starting amount of the substance in question.
- **Equation Structure:** The interface employs multiplication and division to convert between units.
**Factors Available for Calculation:**
- \(1\)
- \(32.00\)
- \(1.90 \times 10^{-4}\)
- \(74.55\)
- \(1.98 \times 10^{-6}\)
- \(2.43 \times 10^{-4}\)
- \(2.97 \times 10^{-6}\)
**Conversion and Calculation Options:**
- **Grams to Moles and Vice Versa:**
- \(9.52 \times 10^{-5}\) g KClO\(_3\)
- \(2\) mol KClO\(_3\)
- \(3\) mol KCl
- \(5.95 \times 10^{-6}\) mol O\(_2\)
- \(6.022 \times 10^{23}\) g O\(_2\)
- \(122.55\) g KCl
**Functional Buttons:**
- **Add Factor:** Allows for the inclusion of an additional conversion or reaction factor.
- **Answer Box:** Entry for the calculated result in the desired unit.
- **Reset Button:** Clears current calculations to restart the problem.
**Resource Note:**
Access additional resources at the bottom of the interface for further exploration and learning.
![**Question 17 of 24**
**Determine the number of molecules of Cr₂O₃ that form when 1.34 x 10³ g of oxygen completely reacts according to the following equation:**
\[ 4 \text{ Cr(s)} + 3 \text{ O}_2\text{(g)} \rightarrow 2 \text{ Cr}_2\text{O}_3\text{(s)} \]
---
**Interactive Calculation Interface:**
- **Starting Amount:** Two boxes for input values.
- **Equation Setup:**
- Multiplication setup with boxes for input, multiplication, and division.
**Controls:**
- **Add Factor:** Enter additional numerical factors.
- **Answer:** Display box for the calculated answer.
- **Reset:** Button to clear inputs.
---
**Available Inputs:**
- **Numerical Values:**
- \( 2.52 \times 10^{25} \)
- \( 3.78 \times 10^{25} \)
- \( 2 \)
- \( 1 \)
- \( 1.34 \times 10^{3} \)
- \( 152.00 \)
- \( 52.00 \)
- **Constants and Conversions:**
- \( 6.022 \times 10^{23} \) (Avogadro's number)
- \( 4 \)
- \( 1.68 \times 10^{25} \)
- \( 32.00 \) (possibly molar mass of O₂)
- \( 3 \)
- **Units for Inputs:**
- g Cr
- g Cr₂O₃
- g O₂
- mol Cr₂O₃
- mol Cr
- molecules Cr₂O₃
- mol O₂
---
**Instructions:**
1. Input the starting amount of oxygen in grams.
2. Use the provided constants and conversion factors to calculate the number of molecules of Cr₂O₃ formed.
3. Check your answer using the equation setup and clear any inputs using the reset button if necessary.
**Note:** Tap or pull up for additional resources.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7127fdb-1b09-43df-9c21-7fe264d46fd8%2F8a4f1335-277c-4bc7-ae21-3164d5fd9f65%2Fd9c1lwj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 17 of 24**
**Determine the number of molecules of Cr₂O₃ that form when 1.34 x 10³ g of oxygen completely reacts according to the following equation:**
\[ 4 \text{ Cr(s)} + 3 \text{ O}_2\text{(g)} \rightarrow 2 \text{ Cr}_2\text{O}_3\text{(s)} \]
---
**Interactive Calculation Interface:**
- **Starting Amount:** Two boxes for input values.
- **Equation Setup:**
- Multiplication setup with boxes for input, multiplication, and division.
**Controls:**
- **Add Factor:** Enter additional numerical factors.
- **Answer:** Display box for the calculated answer.
- **Reset:** Button to clear inputs.
---
**Available Inputs:**
- **Numerical Values:**
- \( 2.52 \times 10^{25} \)
- \( 3.78 \times 10^{25} \)
- \( 2 \)
- \( 1 \)
- \( 1.34 \times 10^{3} \)
- \( 152.00 \)
- \( 52.00 \)
- **Constants and Conversions:**
- \( 6.022 \times 10^{23} \) (Avogadro's number)
- \( 4 \)
- \( 1.68 \times 10^{25} \)
- \( 32.00 \) (possibly molar mass of O₂)
- \( 3 \)
- **Units for Inputs:**
- g Cr
- g Cr₂O₃
- g O₂
- mol Cr₂O₃
- mol Cr
- molecules Cr₂O₃
- mol O₂
---
**Instructions:**
1. Input the starting amount of oxygen in grams.
2. Use the provided constants and conversion factors to calculate the number of molecules of Cr₂O₃ formed.
3. Check your answer using the equation setup and clear any inputs using the reset button if necessary.
**Note:** Tap or pull up for additional resources.
Expert Solution
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
This is a popular solution!
Trending now
This is a popular solution!
Step by step
Solved in 2 steps with 2 images
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Recommended textbooks for you
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781133949640
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:
9781337399074
Author:
John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:
Cengage Learning