Question 16 of 24 Submit How many grams of oxygen gas are produced when 2.43 x 10-ªg of KCIo, are completely reacted according to the following chemical equation: 2 KCIO (s) → 2 KCI(s) + 3 02(g) STARTING AMOUNT ADD FACTOR ANSWER RESET
Question 16 of 24 Submit How many grams of oxygen gas are produced when 2.43 x 10-ªg of KCIo, are completely reacted according to the following chemical equation: 2 KCIO (s) → 2 KCI(s) + 3 02(g) STARTING AMOUNT ADD FACTOR ANSWER RESET
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter5: Principles Of Chemical Reactivity: Energy And Chemical Reactions
Section: Chapter Questions
Problem 116SCQ: Calculate rH for the reaction 2 C(s) + 3 H2(g) + O2(g) C2H5OH() given the information below. C(s)...
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![**Question 16 of 24**
**Chemical Reaction Problem:**
How many grams of oxygen gas are produced when \(2.43 \times 10^{-4}\) g of KClO\(_3\) are completely reacted according to the following chemical equation:
\[ 2 \text{ KClO}_3(s) \rightarrow 2 \text{ KCl}(s) + 3 \text{ O}_2(g) \]
**Calculation Interface:**
- **Starting Amount Box:** This section requires input for the starting amount of the substance in question.
- **Equation Structure:** The interface employs multiplication and division to convert between units.
**Factors Available for Calculation:**
- \(1\)
- \(32.00\)
- \(1.90 \times 10^{-4}\)
- \(74.55\)
- \(1.98 \times 10^{-6}\)
- \(2.43 \times 10^{-4}\)
- \(2.97 \times 10^{-6}\)
**Conversion and Calculation Options:**
- **Grams to Moles and Vice Versa:**
- \(9.52 \times 10^{-5}\) g KClO\(_3\)
- \(2\) mol KClO\(_3\)
- \(3\) mol KCl
- \(5.95 \times 10^{-6}\) mol O\(_2\)
- \(6.022 \times 10^{23}\) g O\(_2\)
- \(122.55\) g KCl
**Functional Buttons:**
- **Add Factor:** Allows for the inclusion of an additional conversion or reaction factor.
- **Answer Box:** Entry for the calculated result in the desired unit.
- **Reset Button:** Clears current calculations to restart the problem.
**Resource Note:**
Access additional resources at the bottom of the interface for further exploration and learning.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7127fdb-1b09-43df-9c21-7fe264d46fd8%2F8a4f1335-277c-4bc7-ae21-3164d5fd9f65%2Fwec2uzi_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 16 of 24**
**Chemical Reaction Problem:**
How many grams of oxygen gas are produced when \(2.43 \times 10^{-4}\) g of KClO\(_3\) are completely reacted according to the following chemical equation:
\[ 2 \text{ KClO}_3(s) \rightarrow 2 \text{ KCl}(s) + 3 \text{ O}_2(g) \]
**Calculation Interface:**
- **Starting Amount Box:** This section requires input for the starting amount of the substance in question.
- **Equation Structure:** The interface employs multiplication and division to convert between units.
**Factors Available for Calculation:**
- \(1\)
- \(32.00\)
- \(1.90 \times 10^{-4}\)
- \(74.55\)
- \(1.98 \times 10^{-6}\)
- \(2.43 \times 10^{-4}\)
- \(2.97 \times 10^{-6}\)
**Conversion and Calculation Options:**
- **Grams to Moles and Vice Versa:**
- \(9.52 \times 10^{-5}\) g KClO\(_3\)
- \(2\) mol KClO\(_3\)
- \(3\) mol KCl
- \(5.95 \times 10^{-6}\) mol O\(_2\)
- \(6.022 \times 10^{23}\) g O\(_2\)
- \(122.55\) g KCl
**Functional Buttons:**
- **Add Factor:** Allows for the inclusion of an additional conversion or reaction factor.
- **Answer Box:** Entry for the calculated result in the desired unit.
- **Reset Button:** Clears current calculations to restart the problem.
**Resource Note:**
Access additional resources at the bottom of the interface for further exploration and learning.
![**Question 17 of 24**
**Determine the number of molecules of Cr₂O₃ that form when 1.34 x 10³ g of oxygen completely reacts according to the following equation:**
\[ 4 \text{ Cr(s)} + 3 \text{ O}_2\text{(g)} \rightarrow 2 \text{ Cr}_2\text{O}_3\text{(s)} \]
---
**Interactive Calculation Interface:**
- **Starting Amount:** Two boxes for input values.
- **Equation Setup:**
- Multiplication setup with boxes for input, multiplication, and division.
**Controls:**
- **Add Factor:** Enter additional numerical factors.
- **Answer:** Display box for the calculated answer.
- **Reset:** Button to clear inputs.
---
**Available Inputs:**
- **Numerical Values:**
- \( 2.52 \times 10^{25} \)
- \( 3.78 \times 10^{25} \)
- \( 2 \)
- \( 1 \)
- \( 1.34 \times 10^{3} \)
- \( 152.00 \)
- \( 52.00 \)
- **Constants and Conversions:**
- \( 6.022 \times 10^{23} \) (Avogadro's number)
- \( 4 \)
- \( 1.68 \times 10^{25} \)
- \( 32.00 \) (possibly molar mass of O₂)
- \( 3 \)
- **Units for Inputs:**
- g Cr
- g Cr₂O₃
- g O₂
- mol Cr₂O₃
- mol Cr
- molecules Cr₂O₃
- mol O₂
---
**Instructions:**
1. Input the starting amount of oxygen in grams.
2. Use the provided constants and conversion factors to calculate the number of molecules of Cr₂O₃ formed.
3. Check your answer using the equation setup and clear any inputs using the reset button if necessary.
**Note:** Tap or pull up for additional resources.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fa7127fdb-1b09-43df-9c21-7fe264d46fd8%2F8a4f1335-277c-4bc7-ae21-3164d5fd9f65%2Fd9c1lwj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Question 17 of 24**
**Determine the number of molecules of Cr₂O₃ that form when 1.34 x 10³ g of oxygen completely reacts according to the following equation:**
\[ 4 \text{ Cr(s)} + 3 \text{ O}_2\text{(g)} \rightarrow 2 \text{ Cr}_2\text{O}_3\text{(s)} \]
---
**Interactive Calculation Interface:**
- **Starting Amount:** Two boxes for input values.
- **Equation Setup:**
- Multiplication setup with boxes for input, multiplication, and division.
**Controls:**
- **Add Factor:** Enter additional numerical factors.
- **Answer:** Display box for the calculated answer.
- **Reset:** Button to clear inputs.
---
**Available Inputs:**
- **Numerical Values:**
- \( 2.52 \times 10^{25} \)
- \( 3.78 \times 10^{25} \)
- \( 2 \)
- \( 1 \)
- \( 1.34 \times 10^{3} \)
- \( 152.00 \)
- \( 52.00 \)
- **Constants and Conversions:**
- \( 6.022 \times 10^{23} \) (Avogadro's number)
- \( 4 \)
- \( 1.68 \times 10^{25} \)
- \( 32.00 \) (possibly molar mass of O₂)
- \( 3 \)
- **Units for Inputs:**
- g Cr
- g Cr₂O₃
- g O₂
- mol Cr₂O₃
- mol Cr
- molecules Cr₂O₃
- mol O₂
---
**Instructions:**
1. Input the starting amount of oxygen in grams.
2. Use the provided constants and conversion factors to calculate the number of molecules of Cr₂O₃ formed.
3. Check your answer using the equation setup and clear any inputs using the reset button if necessary.
**Note:** Tap or pull up for additional resources.
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