4030-2. A candidate for political office commissioned a poll. His staffreceived responses from 900 likely voters and 55% of themsaid they would vote for the candidate. The staff thenconducted a simulation of 1000 more polls of 900 voters,assuming that 55% of voters would vote for their candidate.The output of the simulation is shown in the diagram below.2010-00.49 0.52 0.55Given this output, and assuming a 95% confidence level, themargin of error for the poll is closest toMOES 2 ALPProportion(1) 0.01 (2) 0.03 (3) 0.06 (4) 0.12nFrequency0.580.61

Given- A candidate for political office commissioned a poll. His staff received responses from 900…

Answered: 40 30- 2. A candidate for political…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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Example 3. A certain company's customers is made up of 43% women and 57% men. An aggressive marketing campaign results in an increase of women customers to 46%, according to a sample survey of 50 customers. If the company hadn't run the campaign, how likely is it that 46% of customers are women? Was the campaign worth it? 0.46-0.43
Childhood obesity: A national health survey weighed a sample of 535 boys aged 6 - 11 and found that 83 of them were overweight. They weighed a sample of 474 girls aged 6 - 11 and found that 70 of them were overweight. Can you conclude that the proportion of boys who are overweight is greater than the proportion of girls who are overweight? Let p1 denote the proportion of boys who are overweight and let p2 denote the proportion of girls who are overweight. Use the =α0.05 level of significance and the critical value method with the table. (a) State the appropriate null and alternate hypotheses. (b) Compute the value of the test statistic. (c) State a conclusion at the =α0.05 level of significance.
Hint(s) Check My Work During the first 13 weeks of the television season, the Saturday evening 8:00 P.M. to 9:00 P.M. audience proportions were recorded as ABC 29%, CBS 26%, NBC 23%, and Independents 22%. A sample of 300 homes two weeks after a Saturday night schedule revision yielded the following viewing audience data: ABC 93 homes, CBS 65 homes, NBC 84 homes, and Independents 58 homes. Test with a = 0.05 to determine whether the viewing audience proportions changed. Find the test statistic and p-value. (Round your test statistic to two decimal places. Use Table 3 of Appendix B.) Test statistic = 6.37
R %24 FE %#3 %24 Is the proportion of wildfires caused by humans in the south higher than the proportion of wildfires caused by humans in the west? 374 of the 522 randomly selected wildfires looked at in the south were caused by humans while 390 of the 563 randomly selected wildfires looked at the west were caused by humans. What can be concluded at the a = 0.01 level of significance? a. For this study, we should use Select an answer b. The null and alternative hypotheses would be: :0H H1: Select an answer Select an answer Select an answer (please enter a decimal) Select an answer Select an answer Select an answer (Please enter a decimal) c. The test statistic ? O (please show your answer to 3 decimal places.) d. The p-value (Please show your answer to 4 decimal places.) e. The p-value is ? e a f. Based on this, we should elect an answer the null hypothesis. g. Thus, the final conclusion is that O The results are statistically insignificant at a = 0.01, so there is statistically…
The table below gives the percent of U.S. seniors (aged 65+ years) who used the internet in selected years. Year 2012 2014 2016 2018 2019 % of U.S. seniors using internet 54 57 64 66 73 Use a line of best-fit to predict the percent of U.S. seniors who will use the internet in the year 2022. A. 74 % B.76 % C.77 % D.79 % E.81 %
An economist wonders if corporate productivity in some countries is more volatile than in other countries. One measure of a company's productivity is annual percentage yield based on total company assets.A random sample of leading companies in France gave the following percentage yields based on assets. 4.6 5.4 3.4 3.1 2.4 3.5 2.8 4.4 5.7 3.4 4.1 6.8 2.9 3.2 7.2 6.5 5.0 3.3 2.8 2.5 4.5 Use a calculator to verify that the sample variance is s2 ≈ 2.109 for this sample of French companies.Another random sample of leading companies in Germany gave the following percentage yields based on assets. 3.3 3.2 3.2 4.1 5.4 5.5 5.0 5.4 3.2 3.5 3.7 2.6 2.8 3.0 3.0 2.2 4.7 3.2 Use a calculator to verify that s2 ≈ 1.077 for this sample of German companies.Test the claim that there is a difference (either way) in the population variance of percentage yields for leading companies in France and Germany. Use a 5% level of significance. How could your test conclusion relate to the…
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
C. Test statistics D. Make a decision
R3.23. Tips In restaurants, servers rely on tips as a major source of income. Does serving candy after the meal produce larger tips? To find out, two waiters determined randomly whether or not to give candy to 92 dining parties. They recorded the sizes of the tips and reported that guests getting candy tipped an average of 17.8% of the bill, compared with an average tip of only 15.1% from those who got no candy. ("Sweetening the Till: The Use of Candy to Increase Restaurant Tipping," Journal of Applied Social Psychology 32, no. 2 [2002]: 300-309) a) Was this an experiment or an observational study? Explain. b) Is it reasonable to conclude that the candy caused guests to tip more? Explain. c) The researchers said the difference was statistically sig- nificant. Explain in this context what that means.
How could you solve this problem
Suppose we have the results of a Gallup survey (simple random sampling) which asks participants for their opinions regarding their attitudes toward technology. Based on 1500 interviews, the Gallup report makes confidence statements about its conclusions. If 64% of those interviewed favored modern technology, we can be 95% confident that the percent of those who favored modern technology is a 95% of 64%, or 60.8% b 95% 3% c 64% d 64% 3%
6. A researcher takes a sample of people, and asks them how they would vote for president. When she creates her confidence interval, she has a standard error of .082. If she wanted to get a smaller standard error, what could she do? Group of answer choices Ask a different research question. Take a smaller sample. Take a larger sample. None of the above would create a smaller standard error.

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