4.62. Like the entropy of mixing, a Gibbs energy of mixing for gases can be derived: no of gases Amix G = RT Σ n₁ Inx; i=1 where n, is the number of moles and x; is the mole fraction of the ith gas. (a) Derive this equation. Hint: assume AmixH = 0 and use equation 3.25. (b) Show that mixing is always spon- taneous by demonstrating that AmixG is always less than zero for a mixture of gases. (c) Calculate AmixG when 1.0 mol Ne, 2.0 mol He, and 3.0 mol Ar are mixed at 35.0°C.
4.62. Like the entropy of mixing, a Gibbs energy of mixing for gases can be derived: no of gases Amix G = RT Σ n₁ Inx; i=1 where n, is the number of moles and x; is the mole fraction of the ith gas. (a) Derive this equation. Hint: assume AmixH = 0 and use equation 3.25. (b) Show that mixing is always spon- taneous by demonstrating that AmixG is always less than zero for a mixture of gases. (c) Calculate AmixG when 1.0 mol Ne, 2.0 mol He, and 3.0 mol Ar are mixed at 35.0°C.
Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
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![4.70. Can equation 4.62 be used to calculate ☀ for an ideal
gas? Why or why not?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51435bf2-32bb-499c-aa57-a85dc35bd95d%2F9290aec5-e682-47c3-a74e-e1bedc68749c%2Fascvwzv_processed.png&w=3840&q=75)
Transcribed Image Text:4.70. Can equation 4.62 be used to calculate ☀ for an ideal
gas? Why or why not?
![4.62. Like the entropy of mixing, a Gibbs energy of mixing for
gases can be derived:
no of gases
Amix G = RT Σ n₁ Inx;
i=1
where n, is the number of moles and x; is the mole fraction
of the ith gas. (a) Derive this equation. Hint: assume AmixH = 0
and use equation 3.25. (b) Show that mixing is always spon-
taneous by demonstrating that AmixG is always less than zero
for a mixture of gases. (c) Calculate AmixG when 1.0 mol Ne,
2.0 mol He, and 3.0 mol Ar are mixed at 35.0°C.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F51435bf2-32bb-499c-aa57-a85dc35bd95d%2F9290aec5-e682-47c3-a74e-e1bedc68749c%2Ftk91ews_processed.png&w=3840&q=75)
Transcribed Image Text:4.62. Like the entropy of mixing, a Gibbs energy of mixing for
gases can be derived:
no of gases
Amix G = RT Σ n₁ Inx;
i=1
where n, is the number of moles and x; is the mole fraction
of the ith gas. (a) Derive this equation. Hint: assume AmixH = 0
and use equation 3.25. (b) Show that mixing is always spon-
taneous by demonstrating that AmixG is always less than zero
for a mixture of gases. (c) Calculate AmixG when 1.0 mol Ne,
2.0 mol He, and 3.0 mol Ar are mixed at 35.0°C.
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