4. (Whitlock and Schluter, 2009) Can a human swim faster in water or in syrup? Anexperiment was done in which researchers filled one pool with water mixed with syrupand another pool with normal water. They had 18 swimmers swim laps in both poolsand recorded the relative speed of each swimmer (each swimmer's speed in the syrupypool divided by his or her speed in the water pool). The data, which are approximatelynormally distribution, are as follows:1.08 0.94 1.071.041.02 1.01 0.96 1.041.02 1.01 0.95 1.02 1.081.02 0.96 0.98 0.99 1.02a. Using a critical value from a t distribution, construct a 95% confidence interval forthe mean relative speed if the average relative speed in this sample of swimmers is1.01 and the standard deviation of the relative speed in this sample of swimmers is0.04.b. Based on the confidence interval obtained in part a), what can be said about thep-value for the test of hypothesis Ho: the mean relative speed is equal to 1 (i.e.,swimming speed in syrup is the same as in water) versus Ha: the mean relative speedis not equal to 1.

Answered: 4. (Whitlock and Schluter, 2009) Can a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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2. Two types of instruments for measuring the amount of sulfur monoxide in the atmosphere are being compared in an air-pollution experiment. Researchers wish to determine whether the two types of instruments yield measurements having the same variability. The readings in the following table were recorded for the two instruments. Sulfur Monoxide Instrument A Instrument B 0.87 0.74 0.63 0,82 0.75 0.61 0.55 0,76 0,70 080 0.64 0.81 0,68 0,69 0.57 0,65 0,53
Do E) i ii & iii please
A restaurant manager is planning a new layout for the tables in his store. He will be placing tables of 2, tables of 4, and tables of 6 throughout the dining room. To help him decide how many of each he needs, he decides to keep track of all table requests by customers during a 2-week period. Which measure of central tendency would BEST indicate the typical table size needed?
Bighorn sheep are beautiful wild animals found throughout the western United States. Let x be the age of a bighorn sheep (in years), and let y be the mortality rate (percent that die) for this age group. For example, x = 1, y = 14 means that 14% of the bighorn sheep between 1 and 2 years old died. A random sample of Arizona bighorn sheep gave the following information: x 1 2 3 4 5 y 15.8 17.3 14.4 19.6 20.0 Σx = 15; Σy = 87.1; Σx2 = 55; Σy2 = 1,540.45; Σxy = 272 (a) Find x, y, b, and the equation of the least-squares line. (Round your answers for x and y to two decimal places. Round your least-squares estimates to three decimal places.) x = y = b = ŷ = + x (b) Draw a scatter diagram for the data. Plot the least-squares line on your scatter diagram. (c) Find the sample correlation coefficient r and the coefficient of determination r2. (Round your answers to three decimal places.) r = r2 = What percentage of variation in y is…
Bighorn sheep are beautiful wild animals found throughout the western United States. Let x be the age of a bighorn sheep (in years), and let y be the mortality rate (percent that die) for this age group. For example, x = 1, y = 14 means that 14% of the bighorn sheep between 1 and 2 years old died. A random sample of Arizona bighorn sheep gave the following information: x 1 2 3 4 5 y 13.8 19.3 14.4 19.6 20.0 Σx = 15; Σy = 87.1; Σx2 = 55; Σy2 = 1554.45; Σxy = 274b) Find the equation of the least-squares line. (Round your answers to two decimal places.) ŷ = + x (c) Find r. Find the coefficient of determination r2. (Round your answers to three decimal places.) r = r2 = d) Test the claim that the population correlation coefficient is positive at the 1% level of significance. (Round your test statistic to three decimal places.) t =
A financial analyst is examining the relationship between stock prices and earnings per share. She chooses sixteen publicly traded companies at random and records for each the company's current stock price and the company's earnings per share reported for the past 12 months. Her data are given below, with x denoting the earnings per share from the previous year and y denoting the current stock price (both in dollars). A scatter plot of her data is shown in Figure 1. Also given is the product of the earnings per share and the current stock price for each of the sixteen stocks. (These products, written in the column labelled "xy ", may aid in calculations.) Earnings per share, x (in dollars) 36.79 49.84 30.65 30.17 17.66 57.66 37.98 20.65 58.67 13.52 41.83 39.28 43.73 Current stock price, y (in dollars) 1.43 1.56 0.81 1.40 0.77 2.64 1.11 0.70 2.18 0.41 1.80 1.05 1.63 ху 52.6097 77.7504 24.8265 42.238 13.5982 152.2224 42.1578 14.455 127.9006 5.5432 75.294 41.244 71.2799 Current stock…
c. Which of the following is the correct graph of the given data? -ОА. 10 1012 12 10 O C. 12- 81012 1012 Using the graph, explain the dramatic difference between the answers to parts (a) and (b). Choose the correct answer below. OA. The point (10,10) is not an outier, but it does have a strong effect on the least squares line and the correlation coefficient. OB. The point (10,10) does not have any effect on the least squares line and the correlation coefficient. OC. The point (10,10) is an outler that has a weak effect on the least squares line and the correlation coefficient. OD. The point (10,10) is an outlier that has a strong effect on the least squares line and the correlation coefficient.
Bighorn sheep are beautiful wild animals found throughout the western United States. Let x be the age of a bighorn sheep (in years), and let y be the mortality rate (percent that die) for this age group. For example, x = 1, y = 14 means that 14% of the bighorn sheep between 1 and 2 years old died. A random sample of Arizona bighorn sheep gave the following information: x 1 2 3 4 5 y 15.8 17.3 14.4 19.6 20.0 Σx = 15; Σy = 87.1; Σx2 = 55; Σy2 = 1,540.45; Σxy = 272 (a) Find x, y, b, and the equation of the least-squares line. (Round your answers for x and y to two decimal places. Round your least-squares estimates to three decimal places.) x = y = b = ŷ = + x
A father is concerned that his teenage son is watching too much television each day, since his son watches an average of 2 hours per day His son says that his TV habits are no different than those of his friends. Since this father has taken a stats class, he knows that can actually test to see whether or not his son is watching more TV than his peers The father collects a random sample of watching times from boys at his son's high school and gets the following data: 1.9, 2.3, 2.2, 1.9, 1.6, 2.6, 1.4, 2.0, 2.0, 2.2 Find a 95% confidence interval for the true mean number of hours teenagers at that school watch TV. a. Confidence Interval b. Conclusion
Calculate the measures of central tendency for the grouped data and the measures of dispersion for the grouped and ungrouped data.After computing the measures of central tendency and dispersion, interpret the results.In a 50-question midterm exam, 40 students from the subject Creative Leadership at Angeles City University have their scores recorded. Given: r = 35 Class Interval = 6 i = 6 Lowest value = 13 and Highest value = 48 Data: Number Student’s name Midterm exam score 1 Olivia 18 2 Liam 23 3 Emma 18 4 Noah 18 5 Ava 19 6 Oliver 25 7 Sophia 25 8 Ethan 19 9 Isabella 19 10 Lucas 24 11 Mia 13 12 Mason 13 13 Charlotte 26 14 Benjamin 13 15 Amelia 27 16 William 15 17 Harper 26 18 James 17 19 Evelyn 20 20 Henry 20 21 Abigail 27 22 Sebastian 27 23 Emily 22 24 Alexander 28 25 Elizabeth…
#26). Both photos are the same problem.
Prices of diamonds are very sensitive to their weight (measured in carat). For example, the price of a 1 carat diamond tends to be much higher than the price of a 0.99 carats diamond. To study this phenomenon in more detail, we consider two random samples of diamonds, 0.99 carats and 1 carat, each sample of size 23. The average price of 0.99 carats diamonds in the sample is $4451, while the average price of 1 carat diamonds in the sample is $5681. From long-term studies, we know that both the prices of 0.99 carats diamonds and the prices of 1 carat diamonds are normally distributed with standard deviations oj = $1332 (0.99 carats) and o2 = $1613 (1 carat), respectively. (a) Carry out a hypothesis test at significance level 0.01 to evaluate whether the true average price µi of 0.99 carats diamonds is lower than the true average price µ2 of 1 carat diamonds. Specify Ho and Ha, the test statistic, and calculate the p-value or use p-value considerations to conclude. (b) Compute the type II…

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