4. What is the rate law expression for the reaction below based on the experimental data obtained at room temperature? 2 IO, + 5 HSO,™ I2 + 2 SO4* + H2O + 3 HSO," -> T03- volume and concentration 10 ml 20 ml 10 ml HSO3- volume and Time (s) 500s concentration 20 ml 20 ml 40 ml 0.1M 0.01M 125s 0.1M 0.01M 500s 0.1M 0.01M The total volume of the reaction is 60 ml, supplemented with water. 5. What is the specific rate constant for this reaction? 6. What would you expect to happen to the reaction rate for the above reaction ata higher temperature? RERESE

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**Experiment Details for Reaction Rate Analysis**

**Reaction Equation:**

\[ 2 \text{IO}_3^- + 5 \text{HSO}_3^- \rightarrow \text{I}_2 + 2 \text{SO}_4^{2-} + \text{H}_2\text{O} + 3 \text{HSO}_4^- \]

**Data Table:**

| Time (s) | IO\(_{3}^{-}\) Volume (ml) | IO\(_{3}^{-}\) Concentration (M) | HSO\(_{3}^{-}\) Volume (ml) | HSO\(_{3}^{-}\) Concentration (M) |
|----------|----------------------------|----------------------------------|-----------------------------|-----------------------------------|
| 500      | 10                         | 0.1                              | 20                          | 0.01                              |
| 125      | 20                         | 0.1                              | 20                          | 0.01                              |
| 500      | 10                         | 0.1                              | 40                          | 0.01                              |

**Total Volume of Reaction:** 60 ml, supplemented with water.

**Questions:**

4. **Rate Law Expression:**
   - Determine the rate law expression for the given reaction based on the experimental data at room temperature.

5. **Specific Rate Constant:**
   - Calculate the specific rate constant for this reaction.

6. **Effect of Temperature:**
   - Predict how the reaction rate will change if the reaction is conducted at a higher temperature. 

**Notes:**
- Understanding the relationship between reactant concentrations and the time required for the reaction to proceed can help derive the rate law.
- The overall volume of the mixture (60 ml) implies dilution factors for the concentrations of reactants.
- Consider the effect of temperature on the kinetic energy of the reactants, which typically results in increased reaction rates.
Transcribed Image Text:**Experiment Details for Reaction Rate Analysis** **Reaction Equation:** \[ 2 \text{IO}_3^- + 5 \text{HSO}_3^- \rightarrow \text{I}_2 + 2 \text{SO}_4^{2-} + \text{H}_2\text{O} + 3 \text{HSO}_4^- \] **Data Table:** | Time (s) | IO\(_{3}^{-}\) Volume (ml) | IO\(_{3}^{-}\) Concentration (M) | HSO\(_{3}^{-}\) Volume (ml) | HSO\(_{3}^{-}\) Concentration (M) | |----------|----------------------------|----------------------------------|-----------------------------|-----------------------------------| | 500 | 10 | 0.1 | 20 | 0.01 | | 125 | 20 | 0.1 | 20 | 0.01 | | 500 | 10 | 0.1 | 40 | 0.01 | **Total Volume of Reaction:** 60 ml, supplemented with water. **Questions:** 4. **Rate Law Expression:** - Determine the rate law expression for the given reaction based on the experimental data at room temperature. 5. **Specific Rate Constant:** - Calculate the specific rate constant for this reaction. 6. **Effect of Temperature:** - Predict how the reaction rate will change if the reaction is conducted at a higher temperature. **Notes:** - Understanding the relationship between reactant concentrations and the time required for the reaction to proceed can help derive the rate law. - The overall volume of the mixture (60 ml) implies dilution factors for the concentrations of reactants. - Consider the effect of temperature on the kinetic energy of the reactants, which typically results in increased reaction rates.
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