4. Rose stands in front of a mirror and she looks at Jack through it. The perpendicular distances of Rose and Jack from the mirror are 2 m and 4 m respectively. 1 m 2 m k * Jack starts to walk to the right. What is the minimum distance he has to walk so that Rose cannot see his image through the mirror? Show your calculation. U 2m! Rose 4 mi Jack

4. Rose stands in front of a mirror and she looks at Jack through it. The perpendicular distances of Rose and Jack from the mirror are 2 m and 4 m respectively. 1 m 2 m k * Jack starts to walk to the right. What is the minimum distance he has to walk so that Rose cannot see his image through the mirror? Show your calculation. U 2m! Rose 4 mi Jack

Astronomy

1st Edition

ISBN:9781938168284

Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff

Publisher:Andrew Fraknoi; David Morrison; Sidney C. Wolff

Chapter19: Celestial Distances

Section: Chapter Questions

Problem 7E: While a meter is the fundamental unit of length, most distances traveled by humans are measured in...

See similar textbooks

Similar questions

What about when t=7s? How do we calculate that?
I don't understand how i got this homework problem wrong the first time, my initial answer was "7/10"
While a meter is the fundamental unit of length, most distances traveled by humans are measured in miles or kilometers. Why do you think this is?
How do you convert from days to years?
Given points P(41, 47, 49) and Q(-37, 15, 14), what is the distance between P and Q? (Use 4 decimal places.)
I have a question for the square root of units. So I have the formula 2pi√m/k And m=50g and k=32,700 dynes/cm. (dynes is g x cm/sec2) So when I plug everything in and cancel units out im left with √654sec2 My question is does the square root cancel out with sec2 individually so i'll still have to square root 654 or does the square root cancel out with the whole thing and im left with 654 without having to square root it. Therefore leading to 2pi(654sec). Or would it be 2pi(25.6sec)
How do I find the slope or if my graph is correct
I am a bit confused by how you did the first one, and what the answer is.
A new physics unit of distance is created and called the Zarkov. A student informs you 1 Zarkov (1 Za) is exactly equivalent to 8 inches. Convert 4.44 × 10 5 Z a 3 m i n u t e 2to m 3 h r 2. If hard to read: asking you to convert Zarkov's squared over minutes cubed to meters squared over hours cubed. Answer in E notation without units in the box. I am assuming your output units are m 3 h r 2. Note: for some numbers the computer will convert your E notion to another notation without the E...that will not cost you points. To be clear regarding E notation, I will provide an example of what I'm talking about:
Hey, I'm really so sorry for leaving this out, but I completely forgot to tell you that I need the answer in the amount of years it takes. That's totally on me, I apologize. Also, I can't tell if the dot between the two 2s in the answer is a multiplication symbol or a decimal point.
(please type answer only)
I asked this question earlier. I cannot figure out how you multiplied 02 times 2 times 9.8 times 1857. Your answer was 190.8m/s. Am I missing a step?