The Grand Canyon is 6,093 feet (1857 meters) deep. (Ignore air resistance) If you dropped a rock, how fast would it be going when it lands at the bottom? How long would it take to reach the bottom?
The Grand Canyon is 6,093 feet (1857 meters) deep. (Ignore air resistance) If you dropped a rock, how fast would it be going when it lands at the bottom? How long would it take to reach the bottom?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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I asked this question earlier. I cannot figure out how you multiplied
02 times 2 times 9.8 times 1857. Your answer was 190.8m/s. Am I missing a step?
![Name:
Date:
Per:
Freefalling-Level 3 (Ignore air resistance, use 9.8 m/s' for gravntyi
a (m/s²)
-V.
V (m/s) [from, at]
Ax (m) [how far]
V =V +2a(Ax)
2.
V3Dat+V
2.
(s) )
6. The Grand Canyon is 6,093 feet (1857 meters) deep. (Ignore air resistance)
If you dropped a rock, how fast would it be going when it lands at the bottom?
How long would it take to reach the bottom?
a.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff3ecc2a5-09c1-4934-aaa0-37b0421dff3b%2Fa0f04128-62cc-48b5-9f16-3caf0fc4a97e%2F9ch1q9f.jpeg&w=3840&q=75)
Transcribed Image Text:Name:
Date:
Per:
Freefalling-Level 3 (Ignore air resistance, use 9.8 m/s' for gravntyi
a (m/s²)
-V.
V (m/s) [from, at]
Ax (m) [how far]
V =V +2a(Ax)
2.
V3Dat+V
2.
(s) )
6. The Grand Canyon is 6,093 feet (1857 meters) deep. (Ignore air resistance)
If you dropped a rock, how fast would it be going when it lands at the bottom?
How long would it take to reach the bottom?
a.
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