4. In a given population of 1000 individuals, the allele frequencies are a = 0.4 and A = 0.6. What would be the expected genotype frequencies if this population was at HWE? How many individuals would have each genotype? (p2 + 2pq+q2 = 1).
4. In a given population of 1000 individuals, the allele frequencies are a = 0.4 and A = 0.6. What would be the expected genotype frequencies if this population was at HWE? How many individuals would have each genotype? (p2 + 2pq+q2 = 1).
Human Anatomy & Physiology (11th Edition)
11th Edition
ISBN:9780134580999
Author:Elaine N. Marieb, Katja N. Hoehn
Publisher:Elaine N. Marieb, Katja N. Hoehn
Chapter1: The Human Body: An Orientation
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Transcribed Image Text:In a given population of 1000 individuals, the allele frequencies are \( a = 0.4 \) and \( A = 0.6 \). What would be the expected genotype frequencies if this population was at Hardy-Weinberg Equilibrium (HWE)? How many individuals would have each genotype? Use the equation \( p^2 + 2pq + q^2 = 1 \).
1. Calculate \( p^2 \), which represents the frequency of homozygous dominant (AA) individuals.
2. Calculate \( 2pq \), which represents the frequency of heterozygous (Aa) individuals.
3. Calculate \( q^2 \), which represents the frequency of homozygous recessive (aa) individuals.
4. Multiply these frequencies by 1000 to determine the number of individuals with each genotype.
This exercise helps illustrate the principles of genetic variation within a population under the assumptions of Hardy-Weinberg Equilibrium.
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