4. Graph of E(): You should have found that the electric field inside and outside the sphere is: (x Pr 756 62 E = e 726 where 1/4me. Evaluate the electric field at the following distances from the center and complete the table below. Give answers in terms of Q and b which we assume are constants. Assume Q is positive. 7 = 6/4 r = b/2 E 7 = 0 E Use the table above to help complete the graph of E vs. r. Treat Q and b as constants. 3 e 262 K HIN 0 0 b DIN 2 b 7 = b 36 2 4 7 = 26 2b 5b 2 3b 7 = 36

4. Graph of E(): You should have found that the electric field inside and outside the sphere is: (x Pr 756 62 E = e 726 where 1/4me. Evaluate the electric field at the following distances from the center and complete the table below. Give answers in terms of Q and b which we assume are constants. Assume Q is positive. 7 = 6/4 r = b/2 E 7 = 0 E Use the table above to help complete the graph of E vs. r. Treat Q and b as constants. 3 e 262 K HIN 0 0 b DIN 2 b 7 = b 36 2 4 7 = 26 2b 5b 2 3b 7 = 36

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Electric Charges and Fields

One of the fundamental properties is the electromagnetic property. Charge cannot be destroyed by any process and this contributes formally to the law of charge conservation.

Question

4. Graph of E(): You should have found that the electric field inside and outside the sphere is:
(x8*
750
63
.e
E
7 = 0
where X = 1/4me. Evaluate the electric field at the following distances from the center and complete the table
below. Give answers in terms of Q and b which we assume are constants. Assume Q is positive.
r = b/4
r =b/2
E
Է-1 |
K
ܫܪ
HIN
Use the table above to help complete the graph of E vs. r. Treat Q and b as constants.
3 Q
X
e
6²
0
0
b
DIN
E =
K
2
726
b
7 = b
3b
2
for
7 = 26
2b
5b
2
7 = 3b
3b

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