3. The electric field near a charged, large, thin, flat sheet of (let's say plastic) was obtained inExercise 01 by solving a source charge integration problem. The electric field above acharged, flat disk of radius a was found to be:Ē =ok2€1√(a/z)² +1²°Then, we took the limit as the radius a tends toward infinity to obtain the much simplerexpression E Ē =ok.2€280This same simpler equation can be very easily obtained by applying Gauss' Law using anappropriate Gaussian surface that extends above and below a small part of the chargedsheet. Find this derivation (in a book or online) and rewrite it by hand below. Add verbalexplanations to take the reader through the derivation, equation by equation.

Answered: Image /qna-images/answer/9558b3bd-80a7-4050-852d-9abaf6ac1376.jpg

Answered: Then, we took the limit as the radius a…

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