Consider a thin semicircle of radius as shown in figure below. A positive charge q is uniformly distributed around the semicircle. Find the magnitude and direction of resulting electric field at point P which is located at the center of the curvature of the semicircle
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Consider a thin semicircle of radius as shown in figure below. A positive charge q is uniformly distributed around the semicircle. Find the magnitude and direction of resulting electric field at point P which is located at the center of the curvature of the semicircle.
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- A thin glass rod is bent into a semicircle of radius r. A charge +Q is uniformly distributed along the upper half, and a charge –Q is uniformly distributed along the lower half, as shown in the figure. Find:1) The direction of the electric field at the center O of the semicircle as a function of Q and r. 2) The magnitude of the electric field at the center O of the semicircle as a function of Q and r.3) The force felt by a charge q0 = 2.0 x 10-7 C if this charge is placed at point O.A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a circle of radius R (see the figure). The central perpendicular axis through the ring is a z axis, with the origin at the center of the ring. What is the magnitude of the electric field due to the rod at (a) z = 0 and (b) z = ∞? (c) In terms of R, at what positive value of z is that magnitude maximum? (d) If R = 2.21 cm and Q = 4.32 μC, what is the maximum magnitude?A cubic block of aluminum rests on a wooden table in a region where a uniform electric field is directed straight upward. What can be said concerning the charge on the block's top surface?
- answer please vWhen a charge is placed on a metal sphere, it ends up, in equilibrium, distributed uniformly over the outer surface. Use this information to determine the electric field of 7μC7μC charge put on a 3-cm radius aluminum spherical ball at the following two points in space: a point 2.5 cm from the center of the ball (an inside point): find the magnitude of the electric field in N/C. a point 14 cm from the center of the ball (an outside point): find the magnitude of the electric field in N/C.A uniformly charged insulating rod of length 18.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of −7.50 µC. A rectangular rod is bent into the shape of the left half of a circle centered about a point O. (a) Find the magnitude of the electric field (in N/C) at O, the center of the semicircle. N/C (b) Find the direction of the electric field at O, the center of the semicircle. to the leftto the right upwarddownwardinto the pageout of the page (c) What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of −7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? N/C (d) What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of −7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC? to the leftto the right…
- In the figure a sphere, of radius a = 13.2 cm and charge q = 6.00×10-6 C uniformly distributed throughout its volume, is concentric with a spherical conducting shell of inner radius b = 37.0 cm and outer radius c = 39.0 cm . This shell has a net charge of -q. Find expressions for the electric field, as a function of the radius r, within the sphere and the shell (r< a). Evaluate for r=6.6 cm. Find expressions for the electric field as a function of the radius r, between the sphere and the shell (a< r <b). Evaluate for r=25.1 cm. Find expressions for the electric field as a function of the radius r, inside the shell (b< r <c). Evaluate for r=38.0 cmA coaxial cable (two nested cylinders) of length l, inner radius a and outer radius b. Note that l >> a and l >> b. The inner cylinder is charged to +Q and the outer cylinder is charged to −Q. Use Gauss’s Law to calculate the electric field E⃗ at r<a,a<r<b,andr>b.Five charged particles are equally spaced around a semicircle of radius 100 mm, with one particle at each end of the semicircle and the remaining three spaced equally between the two ends. The semicircle lies in the region x<0 of an xy plane, such that the complete circle is centered on the origin. If each particle carries a charge of 6.00 nC , what is the electric field at the origin? Where could you put a single particle carrying a charge of -5.00 nC to make the electric field magnitude zero at the origin?
- In Figure (a) below, a particle of charge +Q produces an electric field of magnitude Epart at point P, at distance R from the particle. In Figure (b), that same amount of charge is spread uniformly along a circular arc that has radius R and subtends an angle 8. The charge on the arc produces an electric field of magnitude Earc at its center of curvature P. For what value of 0 (in º) does Earc = 0.75Epart? (Hint: You will probably resort to a graphical solution.) +Q |▬▬▬R—-|| Number i P (a) AR +Q}/0/2/ (b) Units ° (degree:A thin nonconducting rod with a uniform distribution of positive charge Q is bent into a circle of radius R (see the figure). The central perpendicular axis through the ring is a z axis, with the origin at the center of the ring. What is the magnitude of the electric field due to the rod at (a) z = 0 and (b) z = ∞? (c) In terms of R, at what positive value of z is that magnitude maximum? (d) If R = 2.25 cm and Q = 4.27 μC, what is the maximum magnitude? (a) and (b) are 0. I just need help with C. I know d is 2.9*10^7 as well.Could you please explain, why the electric field will be along - direction?