A uniformly charged insulating rod of length 18.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of −7.50 µC. A rectangular rod is bent into the shape of the left half of a circle centered about a point O. (a) Find the magnitude of the electric field (in N/C) at O, the center of the semicircle.  N/C (b) Find the direction of the electric field at O, the center of the semicircle. to the leftto the right    upwarddownwardinto the pageout of the page (c)

College Physics
11th Edition
ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A uniformly charged insulating rod of length 18.0 cm is bent into the shape of a semicircle as shown in the figure below. The rod has a total charge of −7.50 µC.
A rectangular rod is bent into the shape of the left half of a circle centered about a point O.
(a)
Find the magnitude of the electric field (in N/C) at O, the center of the semicircle.
 N/C
(b)
Find the direction of the electric field at O, the center of the semicircle.
to the leftto the right    upwarddownwardinto the pageout of the page
(c)
What if? What would be the magnitude of the electric field (in N/C) at O if the top half of the semicircle carried a total charge of −7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC?
 N/C
(d)
What would be the direction of the electric field at O if the top half of the semicircle carried a total charge of −7.50 µC and the bottom half, insulated from the top half, carried a total charge of +7.50 µC?
to the leftto the right    upwarddownwardinto the pageout of the page
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