4. A home upstate has a 10 kV power line to its outside transformer. Given thatthe home circuits include one 220 Volt connection to a device, what is theratio of turns in the transformer. i.e., what must be the turns ratio for thetransformer to power 220 volts at the home? How many amps can besupplied to all circuits of the house at one time?

Given values are - Voltage of power line is 10 Kilo Volt or 10000 Volt. Voltage of device…

Answered: 4. A home upstate has a 10 kV power…

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Similar questions

The 40 kVA three-phase transformer is loaded with a load with a back power factor of 0.8, while the loading rate is 50% and it works at maximum efficiency. The primary of this transformer is star- connected and connected to the interphase voltage of 3400 V. The equivalent resistance to the primary is Req1= 15ohm. What is the % voltage of the transformer when operating under the specified load?
I need the answer as soon as possible
A load of 1700W and COS = 0.85 is to be taken from an ideal single-phase transformer. Determine how much active power can be extracted at cos = 0.5 without overloading the transformer. I2=18.2 A (amps) U2= 110V (volts) Answer in Watts. And
3) The results of an open circuit test and a short circuit test In a 450 kVA transformer, 42000/2400 V, 60 Hz are the following: Open circuit test (low voltage side) VCA = 2400 V ICA = 18,1 A PCA = 3785 in Short circuit test (High voltage side) Vcc = 1910 V Icc = 11,9 A PCC3850 W a) Find the equivalent circuit of the transformer referred to the bass side voltage. b) Calculate the efficiency of the transformer at full load with a factor of Power of 0.85 in delay.
Fast plz
i. The input power to a transformer is 100kW. If the maximum efficiency is 95%, find the constant losses at no load and copper loss at maximum efficiency. ii. The copper losses of a 1:1 transformer is 50W at maximum efficiency. If the primary winding resistance is 1 ohms, calculate the load current at maximum efficiency Q 4.
Q2: A 100-ohm resistor is connected to the secondary of an ideal transformer with a turns ratio of 1:4 (primary to secondary). A 10-V rms, 1-kHz voltage source is connected to the primary. Calculate the primary current and the voltage across the 100 - ohm resistor.
With explanation
In a 15KVA, 2000 / 200 V power transformer, the iron and full load copper losses are 375W and 420W respectively. Calculate the efficiency at (i) full load, 0.8 pf, (ii) half load, .55 pf, (iii) Quarter load, 0.4 pf Efficiency at Full load = Efficiency at Half load = Efficiency at Quarter load =
Problem 3: A 60 Hz, 13.5kV/240V, single-phase ideal transformer is used to step-down the voltage of a distribution system. If the low-voltage side of the transformer is to be kept at a constant magnitude of V₂ - 240 V determine the following quantities: a) the value of the load I impedance (connected to the low-voltage side) that will cause the transformer to be fully loaded; b) the value of the load impedance found in a) referred to the high-voltage side of the transformer; c) the value of the load current referred to the low-voltage side of the transformer; and d) the value of the load current referred to the high-voltage side of the transformer.
Find the power absorbed by the 10-0 resistor in the ideal transformer circuit given in the figure. Take Vs=5220¹ V. 202 1:2 ell 502 ww 10 (2 The power absorbed by the 10-02 resistor in the ideal transformer is 640 W
1. A 5-kVA, 110/110-V, single-phase, 50-Hz transformer has full-load efficiency of 95% and an iron loss of 50-W.The transformer is now connected as an autotransformer to a 220-V supply. If it delivers a 5-kW load at unity power factor to a 110-V circuit, calculate the efficiency of the operation and the current drawn by the high-voltage side.

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