Q3A 750 kVA, 11 kV/ 400 V with 5% impedance distribution transformer is to beinstalled in an industrial power network to serve the industrial motor pump asdepicted in Figure Q3.(1) Analyse the short circuit capacity of the transformer (in kVA)(1) Investigate the voltage variation (in percentage) during the motor starting(ii) Recommend a proper size of the transformer if the voltage variation duringthe motor starting is to be limited to a maximum value of 8%Infinite sourceStandard rating (in kVA):150, 250, 300, 400, 500,630, 750, 1,000, 1,250,1,600, 2,000, 2,500750 KVA11kv/ 400VHorse Power = 500 HPMPF=0.8 lagging, Efficiency = 70%Starting inrush current = 6 times

Given that : z=5% =0.05 1) short circuit capacity of transform Isc(pu)=1/z(p0)…

Q3 A 750 kVA, 11 kV/ 400 V with 5% impedance distribution transformer is to be installed in an industrial power network to serve the industrial motor pump as depicted in Figure Q3. (1) Analyse the short circuit capacity of the transformer (in kVA) (1) Investigate the voltage variation (in percentage) during the motor starting (i) Recommend a proper size of the transformer if the voltage variation during the motor starting is to be limited to a maximum value of 8% Infinite source Standard rating (in kVA): 150, 250, 300, 400, 500, 630, 750, 1,000, 1,250, 1,600, 2,000, 2,500 750 kVA 11kV/400V Horse Power = 500 HP MPF=0.8 lagging, Efficiency = 70% Starting inrush current = 6 times

Q3 A 750 kVA, 11 kV/ 400 V with 5% impedance distribution transformer is to be installed in an industrial power network to serve the industrial motor pump as depicted in Figure Q3. (1) Analyse the short circuit capacity of the transformer (in kVA) (1) Investigate the voltage variation (in percentage) during the motor starting (i) Recommend a proper size of the transformer if the voltage variation during the motor starting is to be limited to a maximum value of 8% Infinite source Standard rating (in kVA): 150, 250, 300, 400, 500, 630, 750, 1,000, 1,250, 1,600, 2,000, 2,500 750 kVA 11kV/400V Horse Power = 500 HP MPF=0.8 lagging, Efficiency = 70% Starting inrush current = 6 times

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Example 1: A single-phase, 100-kVA, 1000:100-V, 60-Hz transformer has the following test results: Open-circuit test (HV side open): 100 V, 6 A, 400 W Short-circuit test (LV side shorted): 50 V, 100 A, 1800 W 1. Draw equivalent circuit of the transformer referred to the high-voltage side. Label impedances numerically in ohms and in per unit. 2. Determine the voltage regulation at rated secondary current with 0.6 power factor lagging. Assume the primary is supplied with rated voltage 3. Determine the efficiency of the transformer when the secondary current is 75% of its rated value and the power factor at the load is 0.8 lagging with a secondary voltage of 98 V across the load
Find the elements of the equivalent circuit relative to the secondary of a single-phase transformer. The no-load voltages in the primary and secondary circuits are 200,400 volts, respectively, at a frequency of 50 Hz The primary no-load current at voltage 200 equals 0.7 amps and pulp losses equal to 70 watts Primary resistance and reactance 3.2 , 1.25 In order, the reactance of the resistance and the coil 0.6 , 0.7 Then draw the equivalent circle, explaining the values
Draw a complete circuit diagram describing a transformer
4.) A transformer has a primary coil with 300 windings, and secondary coil has 400 windings. The input AC power supply is 120 volts (Vrms). A) Is this a step-up or step-down transformer? B) What is the rms voltage across the output terminals (Vrms)? C) What is the peak voltage across the output terminals (Vmax)? Primary Secondary imm ac input
The equivalent circuit impedances of a 20-kVA, 8000/240-V, 60-Hz transformer are to be determined. The open-circuit test and the short- circuit test were performed on the primary side of the transformer, and the following data were taken: Open-circuit test (on primary) Short-circuit test (on primary) 8000 V V= 489 V I0.214 A 2.5 A P= 400 W P= 240 W Find the impedances of the approximate equivalent circuit referred to the primary side, and sketch the circuit.
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A 25 kVA, 2 kV(rms)/100 V(rms) single phase transformer is connected between a 120 V(rms) utility supply and a resistive load. The load current was measured to be 20 A(rms). i. Determine the active power of the load. ii. Determine the primary RMS current. iii. Determine the equivalent resistance of the transformer as seen by the utility supply.