4. 2 KMNO4 + 16 HCI - 5 Cl2 + 2 KCI + 2 MnCl2 + 8 H2O a. Referring to the above reaction equation, if 47.0 g of KMNO4 reacts with 55.0 g of HCI, which one is the limiting reactant for the production of Cl2? Show your calculation with units and the correct number of significant figures. b. How much Cl2 (in grams) can be produced? Make sure to include units and the correct number of significant figures Currently editing

4. 2 KMNO4 + 16 HCI - 5 Cl2 + 2 KCI + 2 MnCl2 + 8 H2O a. Referring to the above reaction equation, if 47.0 g of KMNO4 reacts with 55.0 g of HCI, which one is the limiting reactant for the production of Cl2? Show your calculation with units and the correct number of significant figures. b. How much Cl2 (in grams) can be produced? Make sure to include units and the correct number of significant figures Currently editing

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Consider the general chemical equation 3A+B→2C. Part A. If 1.45 g of A reacts with 1.75 g of B, what is the mass of C? Express your answer with the appropriate units. Part B. If 4.70 g of A reacts to produce 8.95 g of C, what is the mass of B? Express your answer with the appropriate units.
For the following reaction, 0.557 moles of potassium hydroxide are mixed with 0.224 moles of phosphoric acid. potassium hydroxide(aq)+phosphoric acid(aq)= potassium phosphate(aq)+water(l) What is the formula for the limiting reagent? What is the maximum amount of potassium phosphate that can be produced?
3. What mass of NaCl can be produced from 0.55 mol Cl2 in the following reaction? 2 Naa + Cle) → 2 NaCle) d. 88 g a. 0.55 g b. 1.1 g с. 64 g С.
A 0.9 g sample of a mixture of KCl and MgCl2 is treated with excess AgNO3(aq). If 2.37 grams of AgCl(s) are obtained, then what is the percentage by mass of KCl in the original mixture? Your answer must be accurate to two significant digits. Keep several extra digits in your calculations and round off only at the end. Do not include the percent sign (%) as part of your answer. Molar masses (in g mol−1): KCl, 74.55 MgCl2, 95.21 AgCl, 143.35
Manganese commonly occurs in nature as a mineral. The extraction of manganese from the carbonite mineral rhodochrosite. involves a two-step process. In the first step, manganese (II) carbonate and oxygen react to form manganese (IV) oxide and carbon dioxide: 2 MNCO,(s)-0,(g)→2 MnO,(s)-2 C0 (g) In the second step, manganese (IV) oxide and aluminum react to form manganese and aluminum oxide: 3 MnO, (s)- 4 Al(s)-3 Mn(s)–2 Al,O,(s) Write the net chemical equation for the production of manganese from manganese (II) carbonate, oxygen and aluminum. Be sure your equation is balanced.
Magnesium oxide can be made by heating magnesium metal in the presence of the oxygen. The balanced equation for the reaction is 2Mg(s)+O2(g)→2MgO(s) When 10.0 g Mg is allowed to react with 10.5 g O2, 11.8 gMgO is collected. 1. Determine the theoretical yield for the reaction. 2. Determine the percent yield for the reaction.
For the following reaction, 0.358 moles of sulfuric acid are mixed with 0.228 moles of zinc hydroxide. sulfuric acid(aq) + zinc hydroxide(s) → zinc sulfate(aq) + water(e) What is the formula for the limiting reagent? What is the maximum amount of zinc sulfate that can be produced? moles
3. Given: NaCl 1 NiCl₂ + 2 NaOH → 1 Ni(OH)₂ + 2 A student combines 2.44 g of NiCl₂ with 6.44 g NaOH. Determine a. The limiting reactant. b. The mass of the excess reactant that remains at the end of the reaction. c. The number of NaCl molecules that are formed if the reaction is 51% efficient.
A chemist goes into the lab and performs an experiment in which a mixture of 8.47 grams of Zn and 6.03 g of sulfur are reacted. Before starting the experiment they perform the following calculations to predict the maximum (theoretical) yield of zinc sulfide that could be produced. First, write a balanced equation: Zn + 2 S → ZnS2 Second, check to see which reagent is limiting: 1 mole Zn 1 mole ZnS, 1 mole Zn 129.4 g ZnS, 1 mole ZnS, 8.47 g Zn × = 16.8 g ZnS, %3D 65.4 g Zn 1 mole ZnS, 129.4 g ZnS, 1 mole ZnS, 1 mole S 6.03 g S × = 12.2 g ZnS, 32.0 g S 2 moles S Since 6.03 g S produces the least amount of ZnS2, the S is limiting! They obtain an actual yield of 8.25 grams of zinc sulfide. Calculate their percent yield to one decimal place.
For the reaction below, balance the chemical equation and then calculate how many grams of NH3 form when each amount of reactant completely reacts. N2H4 (l) → NH3 (g) + N2 (g) a. 5.3 mol N2H4 b. 32.5 g N2H4 c. 14.7 kg N2H4
a. For the following balanced chemical equation, calculate how many grams of the products would be produced by complete reaction of 0.255 mol of the first reactant. AgNO3(aq) + LiOH(aq) → AgOH(s) + LiNO3(aq) g AgOH g LINO3 b. For the following balanced chemical equation, calculate how many grams of the products would be produced by complete reaction of 0.155 mol of the first reactant. Al2(SO4)3(aq) + 3CaCl₂ (aq) → 2AlCl3 (aq) + 3CaSO4 (8) g AICI, g CaSO4 c. For the following balanced chemical equation, calculate how many grams of the products would be produced by complete reaction of 0.215 mol of the first reactant. CaCO3 (8) + 2HCl(aq) → CaCl2 (aq) + CO2(g) + H₂O(l) g CaCl2 g CO2 g H₂O Submit Answer Retry Entire Group Show Hint 9 more group attempts remaining Previous Next > Save and Exit