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4 Window Help Learning ion 16 of 35 59 $ O Macmillan Learning > achieve.macmillanlearning.com Tue Sep Chapter 4 HW - General, Organic, and Biological Chemistry for Health Sciences - Achieve Classify these alcohols as primary (1°), secondary (2°), or tertiary (3°). 000 000 1° OH CH₂CHCH2 L CH3 2° Answer Bank CH, CH₂CHOH SEP 17 C S MacBook Pro % 55 ^ & 6 7 * 8 9 R T Y U Resources ? Hint Submit Answer CH2CH3 CH₂COH CH2CH3 0 P 3° =1 + 11

4 Window Help Learning ion 16 of 35 59 $ O Macmillan Learning > achieve.macmillanlearning.com Tue Sep Chapter 4 HW - General, Organic, and Biological Chemistry for Health Sciences - Achieve Classify these alcohols as primary (1°), secondary (2°), or tertiary (3°). 000 000 1° OH CH₂CHCH2 L CH3 2° Answer Bank CH, CH₂CHOH SEP 17 C S MacBook Pro % 55 ^ & 6 7 * 8 9 R T Y U Resources ? Hint Submit Answer CH2CH3 CH₂COH CH2CH3 0 P 3° =1 + 11

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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4 Window Help Learning ion 16 of 35 59 $ O Macmillan Learning > achieve.macmillanlearning.com Tue Sep Chapter 4 HW - General, Organic, and Biological Chemistry for Health Sciences - Achieve Classify these alcohols as primary (1°), secondary (2°), or tertiary (3°). 000 000 1° OH CH₂CHCH2 L CH3 2° Answer Bank CH, CH₂CHOH SEP 17 C S MacBook Pro % 55 ^ & 6 7 * 8 9 R T Y U Resources ? Hint Submit Answer CH2CH3 CH₂COH CH2CH3 0 P 3° =1 + 11
Transcribed Image Text:4 Window Help Learning ion 16 of 35 59 $ O Macmillan Learning > achieve.macmillanlearning.com Tue Sep Chapter 4 HW - General, Organic, and Biological Chemistry for Health Sciences - Achieve Classify these alcohols as primary (1°), secondary (2°), or tertiary (3°). 000 000 1° OH CH₂CHCH2 L CH3 2° Answer Bank CH, CH₂CHOH SEP 17 C S MacBook Pro % 55 ^ & 6 7 * 8 9 R T Y U Resources ? Hint Submit Answer CH2CH3 CH₂COH CH2CH3 0 P 3° =1 + 11
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