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(4) Use the power method to approximate the PageRank values for the pages (i.e., the steady state vector q) in part (3). Again the choice of initial vector is unimportant. Let's just use [0.5, 0.5, 0]. i.e. X(0) = [0.5, 0.5, 0]. Note that the values in a vector must sum up to be 1 because the surfer must b in one of the states (visiting one of the pages) at a time. You may stop at X(6). Compare your answ with the following and select all the correct options. U U U r U x(1) X(0) P = [0.26, 0.26, 0.48] x(1) X(0) P = [0.16, 0.16, 0.68] X(2) = x(1) p [0.1952, 0.1952, 0.6096] X(2)x(1) p = [0.2952, 0.2952, 0.4096] X(3) X(2) P = [0.19003733, 0.19003733, 0.61992533] X(3) X(2) p = [0.29003733, 0.29003733, 0.41992533] = X(4) X(3) P = [0.29079452, 0.29079452, 0.41841095] = X(4) X(5) = x(4) P = [0.19068347, 0.19068347, 0.61863306] X(5) X(4) P = [0.29068347, 0.29068347, 0.41863306] = X(3) P [0.19079452, 0.19079452, 0.61841095] = X(6) X(5) P= [0.19069976, 0.19069976, 0.61860048] = X(6) X(5) p = [0.29069976, 0.29069976, 0.41860048] =

(4) Use the power method to approximate the PageRank values for the pages (i.e., the steady state vector q) in part (3). Again the choice of initial vector is unimportant. Let's just use [0.5, 0.5, 0]. i.e. X(0) = [0.5, 0.5, 0]. Note that the values in a vector must sum up to be 1 because the surfer must b in one of the states (visiting one of the pages) at a time. You may stop at X(6). Compare your answ with the following and select all the correct options. U U U r U x(1) X(0) P = [0.26, 0.26, 0.48] x(1) X(0) P = [0.16, 0.16, 0.68] X(2) = x(1) p [0.1952, 0.1952, 0.6096] X(2)x(1) p = [0.2952, 0.2952, 0.4096] X(3) X(2) P = [0.19003733, 0.19003733, 0.61992533] X(3) X(2) p = [0.29003733, 0.29003733, 0.41992533] = X(4) X(3) P = [0.29079452, 0.29079452, 0.41841095] = X(4) X(5) = x(4) P = [0.19068347, 0.19068347, 0.61863306] X(5) X(4) P = [0.29068347, 0.29068347, 0.41863306] = X(3) P [0.19079452, 0.19079452, 0.61841095] = X(6) X(5) P= [0.19069976, 0.19069976, 0.61860048] = X(6) X(5) p = [0.29069976, 0.29069976, 0.41860048] =

Computer Networking: A Top-Down Approach (7th Edition)
Computer Networking: A Top-Down Approach (7th Edition)
7th Edition
ISBN:9780133594140
Author:James Kurose, Keith Ross
Publisher:James Kurose, Keith Ross
Chapter1: Computer Networks And The Internet
Section: Chapter Questions
Problem R1RQ: What is the difference between a host and an end system? List several different types of end...
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(4) Use the power method to approximate the PageRank values for the pages (i.e., the steady state vector q) in part (3). Again the choice of initial vector is unimportant. Let's just use [0.5, 0.5, 0]. i.e., X(0) = [0.5, 0.5, 0]. Note that the values in a vector must sum up to be 1 because the surfer must be in one of the states (visiting one of the pages) at a time. You may stop at X(6). Compare your answers with the following and select all the correct options. U U U r U U x(1) X(0) P = [0.26, 0.26, 0.48] x(1) = X(0) P = [0.16, 0.16, 0.68] x(2) x(1) p = [0.1952, 0.1952, 0.6096] = X(2) X(1) p = [0.2952, 0.2952, 0.4096] X(3) = X(2) p = [0.19003733, 0.19003733, 0.61992533] X(3) X(2) p = [0.29003733, 0.29003733, 0.41992533] = X(4) = x(3) P = [0.29079452, 0.29079452, 0.41841095] X(4) X(5) = x(4) p = [0.19068347, 0.19068347, 0.61863306] = X(3) P = [0.19079452, 0.19079452, 0.61841095] X(5) X(4) P = [0.29068347, 0.29068347, 0.41863306] X(6) X(5) p [0.19069976, 0.19069976, 0.61860048] = X(6) X(5) p = [0.29069976, 0.29069976, 0.41860048] =
Transcribed Image Text:(4) Use the power method to approximate the PageRank values for the pages (i.e., the steady state vector q) in part (3). Again the choice of initial vector is unimportant. Let's just use [0.5, 0.5, 0]. i.e., X(0) = [0.5, 0.5, 0]. Note that the values in a vector must sum up to be 1 because the surfer must be in one of the states (visiting one of the pages) at a time. You may stop at X(6). Compare your answers with the following and select all the correct options. U U U r U U x(1) X(0) P = [0.26, 0.26, 0.48] x(1) = X(0) P = [0.16, 0.16, 0.68] x(2) x(1) p = [0.1952, 0.1952, 0.6096] = X(2) X(1) p = [0.2952, 0.2952, 0.4096] X(3) = X(2) p = [0.19003733, 0.19003733, 0.61992533] X(3) X(2) p = [0.29003733, 0.29003733, 0.41992533] = X(4) = x(3) P = [0.29079452, 0.29079452, 0.41841095] X(4) X(5) = x(4) p = [0.19068347, 0.19068347, 0.61863306] = X(3) P = [0.19079452, 0.19079452, 0.61841095] X(5) X(4) P = [0.29068347, 0.29068347, 0.41863306] X(6) X(5) p [0.19069976, 0.19069976, 0.61860048] = X(6) X(5) p = [0.29069976, 0.29069976, 0.41860048] =
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