4) Three point charges of magnitude Q1 = +2.0 μC, Q2 = +3.0 μС, Q3 == +4.0 μС are located at the corners of atriangle as shown in the figure below. Assume d = 20 cm. (a) Find the resultant force vector acting on Q3. (b)Find the magnitude and direction of the force.dQ360°dQ160°60°Q2d

Approach to solving the question: Given:Distance between charges: d= 20 cm Coulomb's constant:…

Answered: 4) Three point charges of magnitude Q1…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter23: Electric Forces

Section: Chapter Questions

Problem 29PQ: Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric...

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Two particles with charges q1 and q2 are separated by a distance d, and each exerts an electric force on the other with magnitude FE. a. In terms of these quantities, what separation distance would cause the magnitude of the electric force to be halved? b. In terms of these quantities, what separation distance would cause the magnitude of the electric force to be doubled?
The charge unit length on the thin shown below is .What is the force on the point charge q? Solve this problem by first considering the electric force dF on q due to a small segment dx of the rod, which contains charge dx . Then, find the net force by integrating dF over the length of the rod.
(a) Two point charges q1 and q23.00 m apart, and their total charge is 20 C. (a) If the force of repulsion between them is 0.075N, what are magnitudes of the two charges? (b) If one charge attracts the other with a force of 0.150 N, what are the magnitudes of the two charges? Note that you may need to solve a quadratic equation to reach your answer.
Three charged particles are located at the corners of an equilateral triangle as shown in Figure P19.9. Calculate the total electric force on the 7.00-C charge.
A rod 14.0 cm long is uniformly charged and has a total charge of 22.0 C. Determine (a) the magnitude and (b) the direction of the electric field along the axis of the rod at a point 36.0 cm from its center.
Two point charges attract each other with an electric force of magnitude F. If the charge on one of the particles is reduced to one-third its original value and the distance between the particles is doubled, what is the resulting magnitude of the electric force between them? (a) 112F (b) 13F (c) 16F (d) 34F (e) 32F
(a) Find the total Coulomb force on a charge of 2.00 nC located at x = 4.00 cm in Figure 18.52 (b): given that q = 1,00C . (b) Find the x-position at which the electric field is zero in Figure 18.52 (b).
Panicle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 104 C is at (4.00 m, 0), and panicle C of charge 1.00 104 C is at (0, 3.00 m). (a) What is the x-component of the electric force exerted by A on C? (b) What is the y-component of the force exerted by A on C? (c) Find the magnitude of the force exerted by B on C. (d) Calculate the x-component of the force exerted by B on C. (e) Calculate the y-component of the force exerted by B on C. (f) Sum the two x-components to obtain the resultant x-component of the electric force acting on C. (g) Repeat part (f) for the y-component. (h) Find the magnitude and direction of the resultant electric force acting on C.
Two point charges qA = 12.0 C and qB = 45.0 C and a third particle with unknown charge qC are located on the x axis. The particle qA is at the origin, and qB is at x = 15.0 cm. The third particle is to be placed so that each particle is in equilibrium under the action of the electric forces exerted by the other two particles. (a) Is this situation possible? If so, is it possible in more than one way? Explain. Find (b) the required location and (c) the magnitude and the sign of the charge of the third particle.
Rank the magnitudes of the electric field at points A, B, and C in Figure 15.15, with the largest magnitude first. (a) A, B, C (b) A, C, B (c) C, A, B (d) The answer cant be determined by visual inspection. Figure 15.15 The electric field lines for two positive point charges. The points A, B, and C are discussed in Quick Quiz 15.6.
Particle A of charge 3.00 104 C is at the origin, particle B of charge 6.00 101 C is at (4.00 m, 0), and particle C of charge 1.00 104 C is at (0, 3.00 in). We wish to find the net electric force on C. (a) What is the x component of the electric force exerted by A on C? (b) What is the y component of the force exerted by A on C? (c) Kind the magnitude of the force exerted by B on C. (d) Calculate the x component of the force exerted by B on C. (e) Calculate the y component of the force exerted by B on C. (f) Sum the two x components from parts (a) and (d) to obtain the resultant x component of the electric force acting on C. (g) Similarly, find the y component of the resultant force vector acting on C. (h) Kind the magnitude and direction of the resultant electric force acting on C.
Three point charges are arranged as shown in Figure P19.19. (a) Find the vector electric Field that the 6.00-nC and 3.00-nC charges together create at the origin. (b) Find the vector force on the 5.00-nC charge.

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