4,6.4.4,Consider the following data from a repeated-measures design. You want to use arepeated-measures t test to test the null hypothesis Ho: HD 0 (the null hypothesisstates that the mean difference for the general population is zero). The data consist offive observations, each with two measurements, A and B, taken before and after atreatment. Assume the population of the differences in these measurements arenormally distributed.ObservationA123.37.48What is the t statistic for the repeated-measures t test to test the null hypothesis Ho:HD - 0? (two decimals)

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Answered: 4, Consider the following data from a…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You wish to test the following daim (Ha) at a significance level of a = 0.02. Ho:µ = 58.6 Ha:µ < 58.6 You believe the population is normally distributed, but you do not know the standard deviation. You obtain the following sample of data: data 14.2 12 31.5 -11.4 What is the test statistic for this sample? (Report answer accurate to three decimal places.) test statistic = What is the p-value for this sample? (Report answer accurate to four decimal places.) p-value = The p-value is... less than (or equal to) a greater than a This test statistic leads to a decision to... O reject the null accept the null fail to reject the null
Use the following ANOVA table for regression to answer the questions. Analysis of Variance Source DF SS MS F P Regression 1 291.4 291.4 2.01 0.158 Residual Error 174 25230.0 145.0 Total 175 25521.4 Give the F-statistic and p-value.Enter the exact answers.The F-statistic is =The p-value is =
Test the claim below about the mean of the differences for a population of paired data at the level of significance a. Assume the samples are random and dependent, and the populations are normally distributed. Claim: 0 В. Но На > 0 Ha: Ha s0 O C. Ho: Ha = 0 Ha: Hd #0 D. Ho: Ha <0 Ha: Hd 20 O E. Ho: Hd + 0 Ha: Hd F. Ho: Hd 20 Ha: Hd = 0 <0 The test statistic is t= (Round to two decimal places as needed.)
Question 12 An analysis of variance experiment produced portions of a company ANOVA table Source of variations S.S Between groups Within groups d.f MS 25.08 Fral 3 a C. Total 117.72 79 N.B F(3,76)5% 2.724 and F3 79, 5% = 2.70 1. Specify the competing hypothesis in order to determine the population means. 2. Find the missing statistics a, b and c in the ANOVA table. 3. At the 5% significant level, what is the conclusion to the test? • Paragraph B IU A A I E E I I * x, E E E- & V G D I T 12pi
Please provide the answer using minitab
For a repeated-measures study comparing two treatment conditions, a researcher obtains a sample of n = 10 difference scores with a mean of MD = 6 and a variance of s2 = 90. What is the value for the repeated-measures t statistic for these data? Select one: a. 7 b. 6 c. 2 d. 15
Hello! I need answer for letter F only using Anderson-Darling test to support the normal distribution of the data.
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
You may need to use the appropriate technology to answer this question. Submitted The following table contains observed frequencies for a sample of 200. Column Variable Row Variable A B C P 20 44 50 Q 30 26 30 Test for independence of the row and column variables using a = 0.05. State the null and alternative hypotheses. Ho: The column variable is independent of the row variable. H: The column variable is not independent of the row variable. Ho: Variable P is not independent of variable Q. H: Variable P is independent of variable Q. Ho: Variable P is independent of variable Q. H: Variable P is not independent of variable Q. : The column variable is not independent of the row variable. Ho: : The column variable is independent of the row variable. Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value %3D State your conclusion. Reject Ho. We conclude that the column and row variables are…
QUESTION 2 To test the effect of a new medication on pulse rate, the researcher randomly selected the 60 subjects into two groups of 30. New medicine and placebo were given to Group 1 and Group 2, respectively. Below is the Minitab output. Two-Sample T-Test and CI Group Мean StDev SE Mean 1 30 65.20 7.80 1.4 2 30 70.30 8.40 1.5 Difference = mu (1) - mu (2) Estimate for difference: 95% CI for difference: T-Test of difference = 0 (vs not =): T-Value = -2.44 -5.10 (-9.29, -0.91) P-Value=0.018 DF=57 ii) Using to.025,57 = 2.003 shows that the 95% confidence interval for the difference in mean pulse rate between new medication and placebo is (-9.29, -0.91). Hence, interpret its meaning.
Data for fuel economy ratings in mi/gal for different cars are listed below. Each pair of data represents the rating using the Old test and the New test. Old (x) 31 22 23 33 27 21 22 19 31 16 New (y) 25 17 26 26 23 18 19 16 28 19 Find the best predicted value for the New test method given that the Old test method rating was 26. Use a significance level of 0.05.Round your answer to 1 decimal place, if needed.
Refer to the below table. Using an alpha = 0.05, test the claim that IQ scores are the same for children in three different blood lead level groups: low lead level, medium lead level, and high lead level). One-Way Analysis of Variance Summary Table for IQ Measurements for Children among Three Blood Lead Level Groups: Low Lead Level, Medium Lead Level, and High Lead Level. Source df SS MS F p Between-group (treatment) 2 469.1827 2677.864 2.30 0.104 Within-group (error) 118 203.6918 11745.05 Total 120

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