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3/X15 In the design of a conveyor-belt system, small metal blocks are discharged with a velocity of 0.4 mis onto a ramp by the upper conveyor belt shown. If the co- efficient of kinetic friction between the blocks and the ramp is 0.30, calculate the angle which the ramp must make with the horizontal so that the blocks will transfer without slipping to the lower conveyor belt moving at the speed of 0.14 m/s. Ans. 0-16.62 0.40 m/s 1.5 m 0.14 m/s

3/X15 In the design of a conveyor-belt system, small metal blocks are discharged with a velocity of 0.4 mis onto a ramp by the upper conveyor belt shown. If the co- efficient of kinetic friction between the blocks and the ramp is 0.30, calculate the angle which the ramp must make with the horizontal so that the blocks will transfer without slipping to the lower conveyor belt moving at the speed of 0.14 m/s. Ans. 0-16.62 0.40 m/s 1.5 m 0.14 m/s

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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3/X15 3/X15 In the design of a conveyor-belt system, small metal blocks are discharged with a velocity of 0.4 mis onto a ramp by the upper conveyor belt shown. If the co- efficient of kinetic friction between the blocks and the ramp is 0.30, calculate the angle which the ramp must make with the horizontal so that the blocks will transfer without shipping to the lower conveyor belt moving at the speed of 0.14 m/s. Ans. 0-16.620 0.40 m/s Fo 1.5 m 0.14 m/s
Transcribed Image Text:3/X15 3/X15 In the design of a conveyor-belt system, small metal blocks are discharged with a velocity of 0.4 mis onto a ramp by the upper conveyor belt shown. If the co- efficient of kinetic friction between the blocks and the ramp is 0.30, calculate the angle which the ramp must make with the horizontal so that the blocks will transfer without shipping to the lower conveyor belt moving at the speed of 0.14 m/s. Ans. 0-16.620 0.40 m/s Fo 1.5 m 0.14 m/s
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