39 The structures labelled A and B in the image below represent: CTAAATCGGT Allele for red flowers B Enzyme (A Allele for One allele sufficient to white flowers ATAAATCGGT produce half the pigment
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- The following corn loci are on one arm of chromosome9 in the order indicated (the distances between themare shown in map units):c-bz-wx-sh-d-centromere12 8 10 20 10C gives colored aleurone; c, white aleurone.Bz gives green leaves; bz, bronze leaves.Wx gives starchy seeds; wx, waxy seeds.Sh gives smooth seeds; sh, shrunken seeds.D gives tall plants; d, dwarf.A plant from a standard stock that is homozygous for allfive recessive alleles is crossed with a wild-type plantfrom Mexico that is homozygous for all five dominantalleles. The F1 plants express all the dominant allelesand, when backcrossed to the recessive parent, give thefollowing progeny phenotypes:colored, green, starchy, smooth, tall 360white, bronze, waxy, shrunk, dwarf 355colored, bronze, waxy, shrunk, dwarf 40white, green, starchy, smooth, tall 46colored, green, starchy, smooth, dwarf 85white, bronze, waxy, shrunk, tall 84colored, bronze, waxy, shrunk, tall 8white, green, starchy, smooth, dwarf 9colored, green, waxy, smooth,…Choose one plsOn rare occasions, an organism may have three copies of achromosome and therefore has three copies of the genes on thatchromosome (instead of the usual number of two copies). Forsuch a rare organism, the alleles for each gene usually segregateso that a gamete will contain one or two copies of the gene. Let’ssuppose that a rare pea plant has three copies of the chromosomethat carries the height gene. Its genotype is TTt. The plant is alsoheterozygous for the seed color gene, Yy, which is found on adifferent chromosome. With regard to both genes, how manytypes of gametes can this plant make, and in what proportions?(Assume that it is equally likely that a gamete will contain oneor two copies of the height gene.)
- The maternal-effect mutation bicoid (bcd) is recessive. Inthe absence of the bicoid protein product, embryogenesis isnot completed. Consider a cross between a female heterozygousfor the bicoid mutation (bcd+/ bcd-) and a homozygousmale(bcd-/ bcd-). Predict the outcome (normal vs. failed embryogenesis) inthe F1 and F2 generations of the cross described.. The production of pigment in the outer layer of seedsof corn requires each of the three independently assorting genes A, C, and R to be represented by at leastone dominant allele, as specified in Problem 64. Thedominant allele Pr of a fourth independently assortinggene is required to convert the biochemical precursorinto a purple pigment, and its recessive allele pr makesthe pigment red. Plants that do not produce pigmenthave yellow seeds. Consider a cross of a strain of genotype A/A ; C/C ; R/R ; pr/pr with a strain of genotypea/a ; c/c ; r/r ; Pr/Pr.a. What are the phenotypes of the parents?b. What will be the phenotype of the F1?c. What phenotypes, and in what proportions, willappear in the progeny of a selfed F1?d. What progeny proportions do you predict from thetestcross of an F1?In cats, the genotype AA produces tabby fur color; Aa is also a tabby, and aa is black. Another gene at a different locus is epistatic to the gene for fur color. When present in its dominant W form (WW or Ww), this gene blocks the formation of fur color and all the offspring are white; ww individuals develop normal fur color. What fur colors, and in what proportions, would you expect from the cross AaWw Aa Ww?
- The XG locus on the human X chromosome has twoalleles, XG+ and XG. The XG+ allele causes the presence of the Xg surface antigen on red blood cells,while the recessive XG allele does not allow antigento appear. The XG locus is 10 m.u. from the STSlocus. The STS+ allele produces normal activity ofthe enzyme steroid sulfatase, while the recessive STSallele results in the lack of steroid sulfatase activityand the disease ichthyosis (scaly skin). A man withichthyosis and no Xg antigen has a normal daughterwith Xg antigen. This daughter is expecting a child.a. If the child is a son, what is the probability he willlack Xg antigen and have ichthyosis?b. What is the probability that a son would have boththe antigen and ichthyosis?c. If the child is a son with ichthyosis, what is theprobability he will have Xg antigen?. In nature, the plant Plectritis congesta is dimorphic forfruit shape; that is, individual plants bear either winglessor winged fruits, as shown in the illustration.Wingless fruit Winged fruitPlants were collected from nature before floweringand were crossed or selfed with the following results:Number of progenyPollination Winged WinglessWinged (selfed) 91 1*Winged (selfed) 90 30Wingless (selfed) 4* 80Winged × wingless 161 0Winged × wingless 29 31Winged × wingless 46 0Winged × winged 44 0*Phenotype probably has a nongenetic explanation.Interpret these results, and derive the mode ofinheritance of these fruit-shaped phenotypes. Usesymbols. What do you think is the nongeneticexplanation for the phenotypes marked by asterisks inthe table?tl ban o a rne dononant allo le dD), ifs dccessrveallele (h) produces aght bour Another gene has wo alclcs Cm) dork boir n dominant over (b) bionde, A woman ith wooly, blonde lour roarmesan with stranght, dark hai heir daughteT has straight, blonde t What phenorypes and in what proportions can they expcct among fture children? o H X h & 7. The color in Labrador retrievers is an example of epistasis. The two alleles for the pigment gene are: (B) for black coat and its recessive counterpart (b) for chocolate coat. A different autosomal gene affects the expression of color in the coat and has two alleles, (E), which allows the expression of color, and (e), which is epistatic and blocks the expression of the B/b gene. The epistatic allele is recessive and is only expressed as a yellow color in the homozygous condition (ee), regardless of the B and b genotypes. A completely homozygous black lab was mated to a yellow lab, homozygous for the chocolate allele. Their offspring will be the F1…
- A researcher crosses two white-flowered lines ofAntirrhinum plants as follows and obtains the followingresults:pure line 1 × pure line 2↓F1 all whiteF1 × F1↓F2 131 white29 reda. Deduce the inheritance of these phenotypes; useclearly defined gene symbols. Give the genotypes ofthe parents, F1, and F2.b. Predict the outcome of crosses of the F1 with eachparental line.n Figure 4-19, what would be the RF between A/a andB/b in a cross in which purely by chance all meioses hadfour-strand double crossovers in that region?In a certain species of flowering plants with a diploidgenome, four enzymes are involved in the generationof flower color. The genes encoding these four enzymes are on different chromosomes. The biochemical pathway involved is as follows; the figure showsthat either of two different enzymes is sufficient toconvert a blue pigment into a purple pigment.→ white → green → blue → purpleA true-breeding green-flowered plant is mated with atrue-breeding blue-flowered plant. All of the plants inthe resultant F1 generation have purple flowers. F1plants are allowed to self-fertilize, yielding an F2 generation. Show genotypes for P, F1, and F2 plants, andindicate which genes specify which biochemicalsteps. Determine the fraction of F2 plants with thefollowing phenotypes: white flowers, green flowers,blue flowers, and purple flowers. Assume the greenflowered parent is mutant in only a single step ofthe pathway