365 364 a. If two people are selected at random, the probability that they do not have the same birthday (day and month) is 365 365 Explain why this is so. (Ignore leap years and assume 365 days in a year.) The first person can have any birthday, so they can have a birthday on 365 of the 365 days. In order for the second person to not have the same birthday they must have one of the 364 remaining birthdays. (Type whole numbers.) b. If three people are selected at random, find the probability that they all have different birthdays. The probability that they all have different birthdays is (Round to three decimal places as needed.)|

365 364 a. If two people are selected at random, the probability that they do not have the same birthday (day and month) is 365 365 Explain why this is so. (Ignore leap years and assume 365 days in a year.) The first person can have any birthday, so they can have a birthday on 365 of the 365 days. In order for the second person to not have the same birthday they must have one of the 364 remaining birthdays. (Type whole numbers.) b. If three people are selected at random, find the probability that they all have different birthdays. The probability that they all have different birthdays is (Round to three decimal places as needed.)|

College Algebra

10th Edition

ISBN:9781337282291

Author:Ron Larson

Publisher:Ron Larson

Chapter8: Sequences, Series,and Probability

Section8.7: Probability

Problem 6ECP: In Pennsylvania’s Cash 5 game, a player chooses five different numbers from 1 to 43. If these five...

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