4. The values of resistors in a batch follow a normal distribution with a mean of 1 KS2 and a standard deviation of 100 2. Evaluate the probability of a resistor having a resistance a) More than 1.2 k 4. Z=x-M M=1000 5. 5=100. So M DC: 1.2K 0.8K 0.4K 1.IK. 2: +2 -2 -1 +1. a) P(x>1-2K52) = P(=>2) = 1-P(Z<2) = 1 - (0.5 +0.4773) 个 from table -0.0227.

4. The values of resistors in a batch follow a normal distribution with a mean of 1 KS2 and a standard deviation of 100 2. Evaluate the probability of a resistor having a resistance a) More than 1.2 k 4. Z=x-M M=1000 5. 5=100. So M DC: 1.2K 0.8K 0.4K 1.IK. 2: +2 -2 -1 +1. a) P(x>1-2K52) = P(=>2) = 1-P(Z<2) = 1 - (0.5 +0.4773) 个 from table -0.0227.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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