4. The values of resistors in a batch follow a normal distribution with a mean of 1 KS2 and a standard deviation of 100 2. Evaluate the probability of a resistor having a resistance a) More than 1.2 k 4. Z=x-M M=1000 5. 5=100. So M DC: 1.2K 0.8K 0.4K 1.IK. 2: +2 -2 -1 +1. a) P(x>1-2K52) = P(=>2) = 1-P(Z<2) = 1 - (0.5 +0.4773) 个 from table -0.0227.

4. The values of resistors in a batch follow a normal distribution with a mean of 1 KS2 and a standard deviation of 100 2. Evaluate the probability of a resistor having a resistance a) More than 1.2 k 4. Z=x-M M=1000 5. 5=100. So M DC: 1.2K 0.8K 0.4K 1.IK. 2: +2 -2 -1 +1. a) P(x>1-2K52) = P(=>2) = 1-P(Z<2) = 1 - (0.5 +0.4773) 个 from table -0.0227.

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

See similar textbooks

Similar questions

Needs Complete solution with 100 % accuracy.
Please see below. I need help with both of these problems. Note that the answers in the boxes came back as being incorrect.
I need help solving this statistics problem.
For this problem, assume that you weigh 500 duck hatchlings. You find that 93 are slightly underweight, 6 are severely underweight, and the rest are normal. (1) What probability should be assigned to a single duck hatchling's being slightly underweight? (2) What probability should be assigned to a single duck hatchling's being severely underweight? (3) What probability should be assigned to a single duck hatchling's being normal?
The probability of afternoon rain given morning cloud cover >50% is of interest to those forecasting the weather. You can calculate this probability using Bayes' Theorem (below). The probability of morning cloud cover in general is 30% in the area you are concerned with and when there's afternoon rain, morning cloud cover of the kind described above occurs 90% of the time. The probability of rain in general for the area is about 26% of days. From the above information, identify what P(BIA) would be. Express your answer as a proportion, rounded to two decimal places. P(A/B)= = P(B|A)*P(A) P(B)
Please help me with the following question.
Please answer both questions please. I'd really appreicate it. Thank you.
sorry, here is more to the question I posted. Find the probability that none of the households are tuned to CSI: Shoboygan.P(none) = Find the probability that at least one household is tuned to CSI: Shoboygan.P(at least one) = Find the probability that at most one household is tuned to CSI: Shoboygan.P(at most one) =