Within the context of screening test evaluation: P(T | +) = P(T)⋅P(+∣T)P(+)\frac{P(T) \cdot P(+ | T)}{P(+)}P(+)P(T)⋅P(+∣T)​ are the sensitivity and specificity. P(~T | -) = \(\frac{P(~T) \cdot P(- | ~T)}{P(-)} are called the positive predictivity and negative predictivity. Given the data set below, compute the following:   Tuberculosis (T)   X-ray (X) No (T∼\sim∼) Yes (T) Negative (-) 2,350 20 Positive (+) 120 55 Total 2,470 75 a. Sensitivityb. Specificityc. Positive predictivityd. Negative predictivity Medical research has concluded that people experience a common cold roughly two times per year. Assume that the time between colds is normally distributed with a mean of 130 days and a standard deviation of 30 days. a. What is the probability of going 180 or more days between colds?b. What is the probability of going 240 or more days?c. What is the probability of going 230 or less days? Find a z value such that the probability of obtaining a larger z value is only 0.15.

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter4: Polynomial And Rational Functions
Section4.2: Polynomial Functions
Problem 96E: What is the purpose of the Intermediate Value Theorem?
icon
Related questions
Question
  1. Within the context of screening test evaluation:
    1. P(T | +) = P(T)⋅P(+∣T)P(+)\frac{P(T) \cdot P(+ | T)}{P(+)}P(+)P(T)⋅P(+∣T)​ are the sensitivity and specificity.
    2. P(~T | -) = \(\frac{P(~T) \cdot P(- | ~T)}{P(-)} are called the positive predictivity and negative predictivity.
    Given the data set below, compute the following:
  Tuberculosis (T)  
X-ray (X) No (T∼\sim∼) Yes (T)
Negative (-) 2,350 20
Positive (+) 120 55
Total 2,470 75

a. Sensitivity
b. Specificity
c. Positive predictivity
d. Negative predictivity

  1. Medical research has concluded that people experience a common cold roughly two times per year. Assume that the time between colds is normally distributed with a mean of 130 days and a standard deviation of 30 days.

    a. What is the probability of going 180 or more days between colds?
    b. What is the probability of going 240 or more days?
    c. What is the probability of going 230 or less days?

  1. Find a z value such that the probability of obtaining a larger z value is only 0.15.
Expert Solution
steps

Step by step

Solved in 2 steps with 4 images

Blurred answer