36. A 9.75-m ladder with a mass of 23.2 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 245 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.80 rad/s² about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder? (b) What is the ladder's moment of inertia?

36. A 9.75-m ladder with a mass of 23.2 kg lies flat on the ground. A painter grabs the top end of the ladder and pulls straight upward with a force of 245 N. At the instant the top of the ladder leaves the ground, the ladder experiences an angular acceleration of 1.80 rad/s² about an axis passing through the bottom end of the ladder. The ladder's center of gravity lies halfway between the top and bottom ends. (a) What is the net torque acting on the ladder? (b) What is the ladder's moment of inertia?

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

See similar textbooks

Similar questions

During the launch from a board, a diver's angular speed about her center of mass changes from zero to 6.90 rad/s in 310 ms. Her rotational inertia about her center of mass is 12.0 kg · m2. (a) During the launch, what was the magnitude of her average angular acceleration? rad/s2 (b) During the launch, what was the magnitude of the average external torque on her from the board? N. m
An old grindstone, used for sharpening tools, is a solid cylindrical wheel that can rotate about its central axle with negligible friction. The radius of the wheel is 0.330 m. A constant tangential force of 300 N applied to its edge causes the wheel to have an angular acceleration of 0.836 rad/s². (a) What is the moment of inertia of the wheel (in kg. m²)? kg. m² (b) What is the mass (in kg) of the wheel? kg (c) The wheel starts from rest and the tangential force remains constant over a time period of 4.50 s. What is the angular speed (in rad/s) of the wheel at the end of this time period? rad/s
A force of 35 N is applied tangentially to the rim of a solid disk of radius 0.18 m. The disk rotates about an axis through its center and perpendicular to its face with a constant angular acceleration of 120 rad/s2. Determine the mass of the disk.
A uniform disk of radius 0.489 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with the same mass as the disk is attached around the disk's rim. A tangential force of 0.211 N applied at the rim causes an angular acceleration of 0.115 rad/s2. Find the mass of the disk.
A uniform disk of radius 0.521 m and unknown mass is constrained to rotate about a perpendicular axis through its center. A ring with the same mass as the disk is attached around the disk's rim. A tangential force of 0.201 N applied at the rim causes an angular acceleration of 0.107 rad/s2. Find the mass of the disk.
A thin hoop of radius 0.6 m is rotating about its central axis with an angular velocity of +26 rad/s. At t = 0, a force F is applied tangentially to the rim of the hoop, and 4 s later, the hoop comes to a stop. The rotational inertia of the hoop about its central axis is 0.3 kg-m². a. What is the angular acceleration of the hoop while the net torque is applied? Include a plus/minus sign to indicate direction.
A dentist causes the bit of a high-speed drill to accelerate from an angular speed of 1.79 x 10^4 rad/s to an angular speed of 3.13 × 10^4 rad/s. In the process, the bit turns through 3.01 x 10^4 rad. Assuming a constant angular acceleration, how long would it take the bit to reach its maximum speed of 8.46 × 10^4 rad/s, starting from rest?
A solid cylindrical disk has a radius of 0.11 m. It is mounted to an axle that is perpendicular to the circular end at its center. When a 71- N force is applied tangentially to the disk, perpendicular to the radius, the disk acquires an angular acceleration of 200 rad/s². What is the mass of the disk? Number Units α
11.2
A hollow disk with a moment of inertia of 0.5 kg-m2 experiences a net torque of 30 m-N. What is the disk's angular acceleration? 60 rad/s/s 0.02 rad/s/s 30 rad/s/s 15 rad/s/s
M, a solid cylinder (M=2.27 kg, R=0.131 m) pivots on a thin, fixed, frictionless bearing. A string wrapped around the cylinder pulls downward with a force F which equals the weight of a 0.750 kg mass, i.e., F = 7.357 N. Calculate the angular acceleration of the cylinder. R M F
Wile E. Coyote wants to flatten the Road Runner. Wile E. puts food at a pre-determined distance from the edge of a cliff. While the Road Runner eats the food, Wile E. pushes a log down the hill. It rolls without slipping. The radius of the log is 0.3 m. The mass of the log is 80 kg. The rotational inertia of the log is given by I = ½ MR2 . The translational speed of the log just before it leaves the cliff horizontally is 16 m/s. The Road Runner is 10 m below the cliff. If the log is to successfully hit the Road Runner, the food must be place at a precise location from the base of the cliff which you will determine. a. Use only energy considerations and the fact that the log does not slip as it rolls to determine the height it started from, h, before it went over the cliff. b. Determine how far from the edge of the cliff the food needs to be placed so the log lands on the Road Runner. The rotating motion of the log in the air does not affect the motion of the log once it is in the air.…