34. Write the Rouse's equation for distribution of suspended sediment in the vertical of a channel and lebel all the terms. In a wide alluvial channel having suspended sediment load, the depth of flow is 2.8 m. If the suspended load sample indicated a concentration of 700 ppm at a point 30 cm below water surface, estimate the concentration at a point 10 cm above the bed in the same vertical. The exponent in Rouse's equation can be assumed as 0.4.

34. Write the Rouse's equation for distribution of suspended sediment in the vertical of a channel and lebel all the terms. In a wide alluvial channel having suspended sediment load, the depth of flow is 2.8 m. If the suspended load sample indicated a concentration of 700 ppm at a point 30 cm below water surface, estimate the concentration at a point 10 cm above the bed in the same vertical. The exponent in Rouse's equation can be assumed as 0.4.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Similar questions

Write the Rouse's equation for distribution of Suspended sediment in the vertical of a channel and label all the terms. In a wide alluvial channel having suspended sediment load, the depth of flow is 2.8 m. If a suspended load sampler indicated concentration of 700 ppm at a point 30 cm below water surface, estimate the concentration at a point 10 cm above the bed in the same vertical. The exponent in Rouse's equation can be assumedsas 0.4. CS Scanned witA
i need help quick
Relationship of Fr with water saturation 1. How important is the saturation exponent factor n? 2. What influences the magnitude? 3. Mention several methods to find these quantities and include references!
Water content is proportional? A- inversely with hydraulic conductivity. B-directly with soil suction head. C- directly with hydraulic conductivity and inversely with matrix potential head. D- directly with matrix potential head and inversely with hydraulic conductivity. What is the correct answer above??
An oil tank, 20 m in diameter, is built over a site shown below. A specimen of clay in this site (20 mm thickness) double drained was to be tested in an oedometer apparatus, the time required to reach 60% degree of consolidation is 15 minutes. Estimate the differential settlement between the center and perimeter of the tank after 1 year after building the tank. 20 m Oil Tank = 9.4 KN/m Zo.W.I Y = 18 KN/m Kup. Y = 20 KN/m Sand aat G= 27 Clay %w = 20% Р, 3 120 Кра C = 0.2 , C, = 0.04 Rock 3 m 3m 10 m
The results from Henry Darcy's first (10/29/1855-11/02/1855) and fifth (02/17/1856-02/18/1856) experiments are shown below. Using Darcy's Law, compute the hydraulic conductivity (in meters/day) of the two sands used in the experiments. Note: 0. Darcy's Law, Q = -K · A. Ah
SITUATION 7 For the test arrangement shown below, calculate the volume of water discharge in 20 minutes. The cross sectional area of the soil is 4000 sq, mm and k= 4.0 mm/sec. Figure for Situation 7 Flow Overflow 375mm Discharge 225mm Soil 150mm 300mm T.
c) A river has the following hydraulic characteristics, Q = 475 m/s, width 70 m, depth 5.5 m, bed slope 3 x 104. The sediment has a typical diameter D50 = 0.02 m and mass density 2650 kg/m³. Estimate the bed-load transport, Qs using the Einstein-Brown approach.
Solve falling head problem
Design of Canals An irrigation channel designed by Lacey's theory has a mean velocity of 1.5 m/s. The silt factor is unity. The hydraulic mean radius will be:
For a falling-head permeability test, the following are given:length of specimen = 380 mmarea of specimen = 6.5 cm2k = 0.175 cm/minWhat should be the area of the standpipe for the head to dropfrom 650 cm to 300 cm in 8 min?
c) A river has the following hydraulic characteristic, Q = 450 m³/s, width 50 m, depth 6 m, bed slope 3 x 104. The sediment has a typical diameter D50 = 0.01 m and mass density 2650 kg/m'. Estimate the bed-load transport using the Einstein- Brown formulae shown below. O = qs (Ps - p)gD3 (Ps - p)D Y = pR'So Ф = 400 3