34. The smell of fresh-cut pine is due in part to a cyclic alkene called pinene. A graph of the natural logarithm of the vapor pressure of pinene vs. 1/temperature produces a straight line with a slope of -4936.37 K. What is the enthalpy of vaporization of pinene?
34. The smell of fresh-cut pine is due in part to a cyclic alkene called pinene. A graph of the natural logarithm of the vapor pressure of pinene vs. 1/temperature produces a straight line with a slope of -4936.37 K. What is the enthalpy of vaporization of pinene?
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![### Understanding the Enthalpy of Vaporization of Pinene
**Problem Statement:**
The distinct smell of fresh-cut pine is attributed to a cyclic alkene known as pinene. By graphing the natural logarithm of the vapor pressure of pinene against the inverse of temperature (1/temperature), a straight line is produced with a slope of -4936.37 K. Determine the enthalpy of vaporization of pinene.
**Explanation:**
This problem involves analyzing the relationship between vapor pressure and temperature for pinene. The graph described represents a common approach in thermodynamics where the Clausius-Clapeyron equation is used to determine the enthalpy of vaporization (\( \Delta H_{vap} \)).
**Key Concepts:**
- **Pinene:** A naturally occurring compound in pine trees, known for its characteristic pine scent.
- **Vapor Pressure:** The pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases at a given temperature.
- **Clausius-Clapeyron Equation:** This equation relates the natural logarithm of the vapor pressure (P) to the reciprocal of the temperature (1/T):
\[ \ln P = -\frac{\Delta H_{vap}}{R} \left(\frac{1}{T}\right) + C \]
Where:
- \( \ln P \) is the natural logarithm of the vapor pressure.
- \( \Delta H_{vap} \) is the enthalpy of vaporization.
- \( R \) is the universal gas constant (8.314 J/mol·K).
- \( T \) is the temperature in Kelvin.
- \( C \) is a constant.
**Finding the Enthalpy of Vaporization:**
The slope (\(-4936.37\) K) from the graph corresponds to \(-\frac{\Delta H_{vap}}{R}\). Thus, the enthalpy of vaporization can be calculated as:
\[ \Delta H_{vap} = -(\text{slope}) \cdot R \]
Substitute:
\[ \Delta H_{vap} = -(-4936.37 \, \text{K}) \times 8.314 \, \text{J/mol·K} \]
**Conclusion:**
The calculated value will give the enthalpy of vaporization of pinene, which indicates the amount of energy required to](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F277ae00b-d056-42ed-a729-386f4fca5973%2F03f21e97-dce1-4085-a6a1-5d0b463ddc2b%2Fdnluspq_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Understanding the Enthalpy of Vaporization of Pinene
**Problem Statement:**
The distinct smell of fresh-cut pine is attributed to a cyclic alkene known as pinene. By graphing the natural logarithm of the vapor pressure of pinene against the inverse of temperature (1/temperature), a straight line is produced with a slope of -4936.37 K. Determine the enthalpy of vaporization of pinene.
**Explanation:**
This problem involves analyzing the relationship between vapor pressure and temperature for pinene. The graph described represents a common approach in thermodynamics where the Clausius-Clapeyron equation is used to determine the enthalpy of vaporization (\( \Delta H_{vap} \)).
**Key Concepts:**
- **Pinene:** A naturally occurring compound in pine trees, known for its characteristic pine scent.
- **Vapor Pressure:** The pressure exerted by a vapor in thermodynamic equilibrium with its condensed phases at a given temperature.
- **Clausius-Clapeyron Equation:** This equation relates the natural logarithm of the vapor pressure (P) to the reciprocal of the temperature (1/T):
\[ \ln P = -\frac{\Delta H_{vap}}{R} \left(\frac{1}{T}\right) + C \]
Where:
- \( \ln P \) is the natural logarithm of the vapor pressure.
- \( \Delta H_{vap} \) is the enthalpy of vaporization.
- \( R \) is the universal gas constant (8.314 J/mol·K).
- \( T \) is the temperature in Kelvin.
- \( C \) is a constant.
**Finding the Enthalpy of Vaporization:**
The slope (\(-4936.37\) K) from the graph corresponds to \(-\frac{\Delta H_{vap}}{R}\). Thus, the enthalpy of vaporization can be calculated as:
\[ \Delta H_{vap} = -(\text{slope}) \cdot R \]
Substitute:
\[ \Delta H_{vap} = -(-4936.37 \, \text{K}) \times 8.314 \, \text{J/mol·K} \]
**Conclusion:**
The calculated value will give the enthalpy of vaporization of pinene, which indicates the amount of energy required to
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