33. The oxidation of phosphine (PH3) to phosphorus pentoxide (P2Os) is given by the chemical equation. PH3 + O2 ----- P2O5 + H2O Balance the chemical equation. b. How many grams of O2 will react completely with 35.0 grams of PH3? a. 34. An element has the following natural abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26% abundance with 20.99 amu, and 8.82% abundance with 21.99 amu. Calculate the average mass of this element. 35. The pressure of gas is reduced from 1200.0 mm Hg to 850.0 mm Hg as the volume of its container is increased by moving a piston from 85.0 mL. What would the final temperature be if the original temperature was 90.0°C?

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33. The oxidation of phosphine (PH3) to phosphorus pentoxide (P2O5) is given by the chemical equation.
PH3 +
O2
P2O5 +
H2O
Balance the chemical equation.
b. How many grams of O2 will react completely with 35.0 grams of PH3?
a.
34. An element has the foilowing naturai abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26%
abundance with 20.99 amu, and 8.82% abundance with 21.99 amu. Calculate the average mass of this element.
35. The pressure of gas is reduced from 1200.0 mm Hg to 850.0 mm Hg as the volume of its container is increased by
moving a piston from 85.0 mL. What would the final temperature be if the original temperature was 90.0°C?
Transcribed Image Text:33. The oxidation of phosphine (PH3) to phosphorus pentoxide (P2O5) is given by the chemical equation. PH3 + O2 P2O5 + H2O Balance the chemical equation. b. How many grams of O2 will react completely with 35.0 grams of PH3? a. 34. An element has the foilowing naturai abundances and isotopic masses: 90.92% abundance with 19.99 amu, 0.26% abundance with 20.99 amu, and 8.82% abundance with 21.99 amu. Calculate the average mass of this element. 35. The pressure of gas is reduced from 1200.0 mm Hg to 850.0 mm Hg as the volume of its container is increased by moving a piston from 85.0 mL. What would the final temperature be if the original temperature was 90.0°C?
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