300 N/m 2.7 kN • m +3 m-- 3 m - 3 m3 m-

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Calculate the slope at the left support. EI = constant.

Given the (a) equation of the elastic curve for the overhanging beam and (b) the value of EIongation midway between the supports.

Please show complete solution.

300 N/m
2.7 kN • m
+3 m-3 m - 3 m-3 m
Transcribed Image Text:300 N/m 2.7 kN • m +3 m-3 m - 3 m-3 m
(a)
M = -300r + 2700 (1 – 3)° – 150 (a - 6)
+2100 (x – 9) N m
-150z + 2700 (a - 3) - 50 (r - 6)
+ 1050 (z – 9)? + C; N m
-50z + 1350 (r – 3)² – (1 - 6)*
EIV
25
Elv
2
+ 350 (z – 9)° + Cx +C2 N - m
Boundary conditions:
1. 미-0=0
C2 = 0
25
2. 미-9m=0
-50(9)°+1350(6)² - (3)4+Ci(9) = 0
2
C = -1238 N - m?
: -50z + 1350 (z - 3)2
- 20
Elv
+350 (z - 9) – 1238z N- m
(b) Midway between supports ő = -0/-45 m
50(4.5) - 1350(4.5 - 3)? + 1238(4.5)
= 7090 N- m³Į 4
.. EIS
Transcribed Image Text:(a) M = -300r + 2700 (1 – 3)° – 150 (a - 6) +2100 (x – 9) N m -150z + 2700 (a - 3) - 50 (r - 6) + 1050 (z – 9)? + C; N m -50z + 1350 (r – 3)² – (1 - 6)* EIV 25 Elv 2 + 350 (z – 9)° + Cx +C2 N - m Boundary conditions: 1. 미-0=0 C2 = 0 25 2. 미-9m=0 -50(9)°+1350(6)² - (3)4+Ci(9) = 0 2 C = -1238 N - m? : -50z + 1350 (z - 3)2 - 20 Elv +350 (z - 9) – 1238z N- m (b) Midway between supports ő = -0/-45 m 50(4.5) - 1350(4.5 - 3)? + 1238(4.5) = 7090 N- m³Į 4 .. EIS
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