30.0 mL of a 0.20 M solution of the weak base methylamine is titrated with 0.10 M nitric acid (HNO3). The Kb of methylamine can be found in Appendix I. Calculate the pH at each volume of base addition as listed below and report your answer to two decimal places The initial pH (after 0.0 mL of nitric acid addition) is The pH after 10.0 mL of nitric acid addition is The pH after 30.0 mL of nitric acid addition is The pH after 60.0 mL of nitric acid addition is The pH after 65.0 mL of nitric acid addition is
30.0 mL of a 0.20 M solution of the weak base methylamine is titrated with 0.10 M nitric acid (HNO3). The Kb of methylamine can be found in Appendix I. Calculate the pH at each volume of base addition as listed below and report your answer to two decimal places The initial pH (after 0.0 mL of nitric acid addition) is The pH after 10.0 mL of nitric acid addition is The pH after 30.0 mL of nitric acid addition is The pH after 60.0 mL of nitric acid addition is The pH after 65.0 mL of nitric acid addition is
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Question 9:
30.0 mL of a 0.20 M solution of the weak base methylamine is titrated
with 0.10 M nitric acid (HNO3). The Kb of methylamine can be found
in Appendix I. Calculate the pH at each volume of base addition as
listed below and report your answer to two decimal places
The initial pH (after 0.0 mL of nitric acid addition) is
The pH after 10.0 mL of nitric acid addition is
The pH after 30.0 mL of nitric acid addition is
The pH after 60.0 mL of nitric acid addition is
The pH after 65.0 mL of nitric acid addition is
100](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F62827abc-7322-4cdd-a99c-db4ca5ddae13%2Ffcc6788b-3c0b-4be9-8c73-9b38bd1455e8%2Fn7rh87e_processed.png&w=3840&q=75)
Transcribed Image Text:Question 9:
30.0 mL of a 0.20 M solution of the weak base methylamine is titrated
with 0.10 M nitric acid (HNO3). The Kb of methylamine can be found
in Appendix I. Calculate the pH at each volume of base addition as
listed below and report your answer to two decimal places
The initial pH (after 0.0 mL of nitric acid addition) is
The pH after 10.0 mL of nitric acid addition is
The pH after 30.0 mL of nitric acid addition is
The pH after 60.0 mL of nitric acid addition is
The pH after 65.0 mL of nitric acid addition is
100
![Acid Name
Perchloric acid
Sulfuric acid
Hydrochloric acid
Nitric acid
Hydronium ion
Sulfurous acid
Hydrogen sulfate ion
Phosphoric acid
Hexaaquairon(III) ion
Hydrofluoric acid
Nitrous acid
Formic acid
Benzoic acid
Acetic acid
Propanoic acid
Hexaaquaaluminium ion
Carbonic acid
Hexaaquacopper(ll) ion
Ionization Constants for Some Acids and Their Conjugate Bases at 25°C
Ka
Formula
Kb
Base name
very small
very small
very small
very small
Ammonium ion
Hydrocyanic acid
Hexaaquairon(II) ion
Hydrogen carbonate ion
Hexaaquanickel(l) ion
Hydrogen phosphate ion
Water
Hydrogen sulfide ion
Ethanol
Ammonial
Hydrogen
Formula
HCIO4
H₂SO4
HCI
HNO3
H₂O+
H₂SO₂
HSO4
H₂PO4
[Fe(H₂O)]³+
HF
HNO₂
HCO₂H
Hydrogen sulfide
H₂S
Dihydrogen phosphate ion H₂PO4
Hydrogen sulfite ion
HSO3™
Hypochlorous acid
HCIO
Hexaaqualead(II) ion
Hexaaquacobalt(II) ion
Boric acid
Coty COzH 6.3x10
CH,COH
1.8x10
CH₂CH₂CO₂H 1.3x10
[Al(H₂O)]³+ 7.9x10
H₂CO3
large
large
large
large
1.0
NH4+
HCN
CIO4
HSO4
cr
NO3™
H₂O
1.2x10²
HSO,
1.2x10-² SO4²-
[Fe(H₂O)]²+
HCO,
[Ni(H₂O)]²+
HPO4²-
7.5x10 H₂PO4
6.3x10³
7.2x10
F-
4.5x10+
NO₂
1.8x10 HCO₂™
[Cu(H₂0)]²+ 1.6x107
H₂O
HS™
C₂H5OH
NH3
H₂
C6H5CO₂™
CH3CO₂
2.4x108
6.3x10-
1.0x107
6.2x10
HPO4²-
1.6x10-7
6.2x10- SO₂²-
1.6x10-7
2.9x107
3.5x10 CIO-
[Pb(H₂0)]²+ 1.5x10 [Pb(H₂O),OH]* 6.7x107
[Co(H₂O) ¹2+ 1.3x10 [Co(H₂O) OH]* 7.7x10-6
B(OH),(H₂O) 7.3x10-1⁰ B(OH)4
1.4x10
5.6×10-10 Nha
1.8x10
4.0x10-10 CN
2.5x10-6
3.1x10
[Fe(H₂O), OH]2+ 1.6x10-¹2
4.2x107 HCO₂™
[Cu(H₂O)OH]*
CH₂CH₂CO₂ 7.7x10-10 Propanoate ion
[Al(H₂O)OH)²+ 1.3x10
1.0x10 HS
3.2x10-10 [Fe(H₂O), OH]*
4.8x10-11 CO²-
1.0x10-14
8.3x10-13 Hydrogen sulfite ion
8.3x10-13 Sulfate ion
1.3x10-12 Dihydrogen phosphate ion
Pentaaquahydroxoiron (III) ion
1.0x10-¹4 OH
1.0x10-19 S²-
Perchlorate ion
Hydrogen sulfate ion
Chloride ion
Nitrate ion
Water
very small C₂H5O
very small NH₂™
very small H™
1.4x10-¹1 Fluoride ion
2.2x10-¹1 Nitrite ion
5.6x10-¹1 Formate ion
1.6x10-10 Benzoate ion
5.6x10-10 Acetate ion
2.1x10+
2.5x10-¹¹ [Ni(H₂O)OH]* 4.0x10+
3.6x10-13 PO4³-
2.8x10²
1.0
1.0x105
large
large
large
Pentaaquahydroxoaluminum ion
Hydrogen carbonate ion
Pentaaquahydroxocopper(II) ion
Hydrogen sulfide ion
Hydrogen phosphate ion
Sulfite ion
Hypochlorite ion
Pentaaquahydroxolead(II) ion
Pentaaquahydroxocobalt(II) ion
Tetrahydroxoborate ion
Ammonia
Cyanide ion
Pentaaquahydroxoiron (II) ion
Carbonate ion
Pentaaquahydroxonickel(II) ion
Phosphate ion
Hydroxide ion
Sulfide ion
Ethoxide ion
Amide ion
Hydride ion](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F62827abc-7322-4cdd-a99c-db4ca5ddae13%2Ffcc6788b-3c0b-4be9-8c73-9b38bd1455e8%2Fuqt9xkr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Acid Name
Perchloric acid
Sulfuric acid
Hydrochloric acid
Nitric acid
Hydronium ion
Sulfurous acid
Hydrogen sulfate ion
Phosphoric acid
Hexaaquairon(III) ion
Hydrofluoric acid
Nitrous acid
Formic acid
Benzoic acid
Acetic acid
Propanoic acid
Hexaaquaaluminium ion
Carbonic acid
Hexaaquacopper(ll) ion
Ionization Constants for Some Acids and Their Conjugate Bases at 25°C
Ka
Formula
Kb
Base name
very small
very small
very small
very small
Ammonium ion
Hydrocyanic acid
Hexaaquairon(II) ion
Hydrogen carbonate ion
Hexaaquanickel(l) ion
Hydrogen phosphate ion
Water
Hydrogen sulfide ion
Ethanol
Ammonial
Hydrogen
Formula
HCIO4
H₂SO4
HCI
HNO3
H₂O+
H₂SO₂
HSO4
H₂PO4
[Fe(H₂O)]³+
HF
HNO₂
HCO₂H
Hydrogen sulfide
H₂S
Dihydrogen phosphate ion H₂PO4
Hydrogen sulfite ion
HSO3™
Hypochlorous acid
HCIO
Hexaaqualead(II) ion
Hexaaquacobalt(II) ion
Boric acid
Coty COzH 6.3x10
CH,COH
1.8x10
CH₂CH₂CO₂H 1.3x10
[Al(H₂O)]³+ 7.9x10
H₂CO3
large
large
large
large
1.0
NH4+
HCN
CIO4
HSO4
cr
NO3™
H₂O
1.2x10²
HSO,
1.2x10-² SO4²-
[Fe(H₂O)]²+
HCO,
[Ni(H₂O)]²+
HPO4²-
7.5x10 H₂PO4
6.3x10³
7.2x10
F-
4.5x10+
NO₂
1.8x10 HCO₂™
[Cu(H₂0)]²+ 1.6x107
H₂O
HS™
C₂H5OH
NH3
H₂
C6H5CO₂™
CH3CO₂
2.4x108
6.3x10-
1.0x107
6.2x10
HPO4²-
1.6x10-7
6.2x10- SO₂²-
1.6x10-7
2.9x107
3.5x10 CIO-
[Pb(H₂0)]²+ 1.5x10 [Pb(H₂O),OH]* 6.7x107
[Co(H₂O) ¹2+ 1.3x10 [Co(H₂O) OH]* 7.7x10-6
B(OH),(H₂O) 7.3x10-1⁰ B(OH)4
1.4x10
5.6×10-10 Nha
1.8x10
4.0x10-10 CN
2.5x10-6
3.1x10
[Fe(H₂O), OH]2+ 1.6x10-¹2
4.2x107 HCO₂™
[Cu(H₂O)OH]*
CH₂CH₂CO₂ 7.7x10-10 Propanoate ion
[Al(H₂O)OH)²+ 1.3x10
1.0x10 HS
3.2x10-10 [Fe(H₂O), OH]*
4.8x10-11 CO²-
1.0x10-14
8.3x10-13 Hydrogen sulfite ion
8.3x10-13 Sulfate ion
1.3x10-12 Dihydrogen phosphate ion
Pentaaquahydroxoiron (III) ion
1.0x10-¹4 OH
1.0x10-19 S²-
Perchlorate ion
Hydrogen sulfate ion
Chloride ion
Nitrate ion
Water
very small C₂H5O
very small NH₂™
very small H™
1.4x10-¹1 Fluoride ion
2.2x10-¹1 Nitrite ion
5.6x10-¹1 Formate ion
1.6x10-10 Benzoate ion
5.6x10-10 Acetate ion
2.1x10+
2.5x10-¹¹ [Ni(H₂O)OH]* 4.0x10+
3.6x10-13 PO4³-
2.8x10²
1.0
1.0x105
large
large
large
Pentaaquahydroxoaluminum ion
Hydrogen carbonate ion
Pentaaquahydroxocopper(II) ion
Hydrogen sulfide ion
Hydrogen phosphate ion
Sulfite ion
Hypochlorite ion
Pentaaquahydroxolead(II) ion
Pentaaquahydroxocobalt(II) ion
Tetrahydroxoborate ion
Ammonia
Cyanide ion
Pentaaquahydroxoiron (II) ion
Carbonate ion
Pentaaquahydroxonickel(II) ion
Phosphate ion
Hydroxide ion
Sulfide ion
Ethoxide ion
Amide ion
Hydride ion
Expert Solution
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Step 1: Given Information
30.0 mL of a 0.20 M solution of the weak base methylamine is titrated with 0.10 M nitric acid (HNO3).
Kb of methylamine = 4.4×10-4
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