Given a 1.00 L solution that is 0.60 M HF and 1.00 M KF, calculate the pH after 0.14 mol NaOH is added, and calculate the pH after 0.16 mol HCI is added to the original solution. Ka = 7.2x10-4 pH = pH = when NaOH is added when HCI is added

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Given a 1.00 L solution that is 0.60 M HF and 1.00 M KF, calculate the pH after 0.14 mol NaOH is added, and calculate the pH after 0.16 mol HCl is added to the original solution.

Ka = 7.2×10-4

**Problem Statement:**

Given a 1.00 L solution that is 0.60 M HF (hydrofluoric acid) and 1.00 M KF (potassium fluoride), calculate the pH after 0.14 mol NaOH (sodium hydroxide) is added, and calculate the pH after 0.16 mol HCl (hydrochloric acid) is added to the original solution.

\( K_a = 7.2 \times 10^{-4} \)

- **pH = _______** when NaOH is added
- **pH = _______** when HCl is added

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Transcribed Image Text:**Problem Statement:** Given a 1.00 L solution that is 0.60 M HF (hydrofluoric acid) and 1.00 M KF (potassium fluoride), calculate the pH after 0.14 mol NaOH (sodium hydroxide) is added, and calculate the pH after 0.16 mol HCl (hydrochloric acid) is added to the original solution. \( K_a = 7.2 \times 10^{-4} \) - **pH = _______** when NaOH is added - **pH = _______** when HCl is added **Options:** - **Submit Answer** - **Try Another Version** **Note:** 1 item attempt remaining.
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