An analytical chemist is titrating 120.4 mL of a 0.5800M solution of piperidine (C5H₁0NH) with a 0.7600M solution of HNO3. The pK, of piperidine is 2.89. Calculate the pH of the base solution after the chemist has added 64.0 mL of the HNO3 solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO3 solution added. Round your answer to 2 decimal places. pH = X S

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An analytical chemist is titrating 120.4 mL of a 0.5800 M solution of piperidine (C₅H₁₀NH) with a 0.7600 M solution of HNO₃. The pK_b of piperidine is 2.89. Calculate the pH of the base solution after the chemist has added 64.0 mL of the HNO₃ solution to it.

*Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO₃ solution added.*

Round your answer to 2 decimal places.

pH = [Input Box] [Buttons for Submission and Reset]
Transcribed Image Text:An analytical chemist is titrating 120.4 mL of a 0.5800 M solution of piperidine (C₅H₁₀NH) with a 0.7600 M solution of HNO₃. The pK_b of piperidine is 2.89. Calculate the pH of the base solution after the chemist has added 64.0 mL of the HNO₃ solution to it. *Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HNO₃ solution added.* Round your answer to 2 decimal places. pH = [Input Box] [Buttons for Submission and Reset]
Expert Solution
Step 1

Volume of piperidine= 120.4 mL 

Volume of piperidine=0.5800M 

Concentration of HNO3=0.7600M 

Volume of HNO4=64.0mL 

pKb of piperidine=2.89 

pH of base solution=?

 

 

 

 

 

 

 

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