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30² (atbi) (c+di) < 80 a= 9 b= 3 : > d=-2 (9+31) (6 + (-2) i) 54 + 181 + (-18i) + (-67 (-1) 54 +6 60 60 is a real number between 30 and 80 Puzzle #2. (a+Bi) (0+ [i] = 34 +8i 0 (atbi) (c+di)= 34 + 8i b = 5 d=-2 . a= 6 C = 4 (6 + 5i) (4 + (-2) i ) = 24 + 20i † (-12)i + (-10) (-1) = 34 + 81 ↓ ie= (6 +5₁) (4 + (-2);) = 34 + 8i

30² (atbi) (c+di) < 80 a= 9 b= 3 : > d=-2 (9+31) (6 + (-2) i) 54 + 181 + (-18i) + (-67 (-1) 54 +6 60 60 is a real number between 30 and 80 Puzzle #2. (a+Bi) (0+ [i] = 34 +8i 0 (atbi) (c+di)= 34 + 8i b = 5 d=-2 . a= 6 C = 4 (6 + 5i) (4 + (-2) i ) = 24 + 20i † (-12)i + (-10) (-1) = 34 + 81 ↓ ie= (6 +5₁) (4 + (-2);) = 34 + 8i

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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using my work can you help me with the reflection. specifically about using i to the power of n and it’s computation please
Reflection With regard to the two puzzles, please comment about the process of multiplying complex numbers. in With regard to: did you observe it while solving the two puzzles, and if yes, how did you compute its value?
Transcribed Image Text:Reflection With regard to the two puzzles, please comment about the process of multiplying complex numbers. in With regard to: did you observe it while solving the two puzzles, and if yes, how did you compute its value?
E Puzzle # 30² (atbi) (c + di) ²80 C-6 d=2 a q b= 3 (9 +31) (6 + (-2) i) 54 + 181 + (-18i) + (-67 (-1) 54 +6 = 60 60 is a real number between 30 and 80 Puzzle #2. Kato:) (0+0i) = 34+8; (atbi) (c+di) = 34 + 8i a= 6 b = 5 C- 4 d=2 (6 + 5i) (4 + (-2) i) = 24 + 20i † (-12)i + (-10) (-1) 34 +81 ↓ ie= (6 +51) (4 + (-2);) = 34 + 81
Transcribed Image Text:E Puzzle # 30² (atbi) (c + di) ²80 C-6 d=2 a q b= 3 (9 +31) (6 + (-2) i) 54 + 181 + (-18i) + (-67 (-1) 54 +6 = 60 60 is a real number between 30 and 80 Puzzle #2. Kato:) (0+0i) = 34+8; (atbi) (c+di) = 34 + 8i a= 6 b = 5 C- 4 d=2 (6 + 5i) (4 + (-2) i) = 24 + 20i † (-12)i + (-10) (-1) 34 +81 ↓ ie= (6 +51) (4 + (-2);) = 34 + 81
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