-4- 2i 4+2i RR,+9R, -6– 3i -9+18i 5 5 -1 3i -4- 2i 4+2i| 5 0 -3i 0 3i 0 5 R-→SR;/(-6-31) 1 -1
-4- 2i 4+2i RR,+9R, -6– 3i -9+18i 5 5 -1 3i -4- 2i 4+2i| 5 0 -3i 0 3i 0 5 R-→SR;/(-6-31) 1 -1
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
Question
please explain this step for me, I cannot figure out how to get this step
Expert Solution
Step 1
We have the matrix
Now, we need to apply the operation
This means we need to multiply row 2 by
The first element in row 2 is 0. Therefore, multiplying 0 by will result in 0 only.
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