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3.66. (a) Find I and V in the four circuits in Fig. P3.66 using the ideal diode model. (b) Repeat using the constant voltage drop model with Von =0.65 V. Q +3 V +5 V 16 k2 16 k2 -5 V -7 V (a) (b) 9 +5 V 9 +7 V 16 k2 16 k2 6 -3 V 6 -5 V (c) (d) Figure P3.66

3.66. (a) Find I and V in the four circuits in Fig. P3.66 using the ideal diode model. (b) Repeat using the constant voltage drop model with Von =0.65 V. Q +3 V +5 V 16 k2 16 k2 -5 V -7 V (a) (b) 9 +5 V 9 +7 V 16 k2 16 k2 6 -3 V 6 -5 V (c) (d) Figure P3.66

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
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### Piecewise Linear Models and Diode Analysis **Text 3.66:** Piecewise linear models should be used for circuit analysis. In Part (a), assume the diode switches from OFF to ON when the diode voltage is zero volts. Part (b) involves using the diode model with a 0.65 volt battery, indicating the switch from OFF to ON. To methodically analyze each circuit, check for any contradictions with the diode model and circuit operation when the diode is assumed either ON or OFF. Sketching a piecewise linear I-V characteristic is an advisable approach. Prepare a table to summarize your results. #### Problem 3.66: Task (a) Find the current (\(I\)) and voltage (\(V\)) in the four circuits illustrated in Fig. P3.66 using the ideal diode model. (b) Repeat the process using the constant voltage drop model with \(V_{\text{on}} = 0.65\) V. #### *Circuit Descriptions:* - **Figure P3.66a:** - Circuit includes a 5V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is at -5V. - **Figure P3.66b:** - Circuit includes a 3V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is grounded (0V), and the other connection is at -7V. - **Figure P3.66c:** - Circuit contains a 7V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is at -3V. - **Figure P3.66d:** - Circuit includes a 5V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is at -5V. #### Analysis Approach: 1. **Ideal Diode Model:** - Assume the diode acts as a short circuit when ON and an open circuit when OFF. - Analyze resulting circuit conditions for current (\(I\)) and voltage (\(V\)) across components. 2. **Constant Voltage Drop Model:** - The diode turns ON with a forward voltage drop of 0.65V. - Determine current (\(I\)) and voltage (\(V\)) considering this voltage drop. #### Conclusion:
Transcribed Image Text:### Piecewise Linear Models and Diode Analysis **Text 3.66:** Piecewise linear models should be used for circuit analysis. In Part (a), assume the diode switches from OFF to ON when the diode voltage is zero volts. Part (b) involves using the diode model with a 0.65 volt battery, indicating the switch from OFF to ON. To methodically analyze each circuit, check for any contradictions with the diode model and circuit operation when the diode is assumed either ON or OFF. Sketching a piecewise linear I-V characteristic is an advisable approach. Prepare a table to summarize your results. #### Problem 3.66: Task (a) Find the current (\(I\)) and voltage (\(V\)) in the four circuits illustrated in Fig. P3.66 using the ideal diode model. (b) Repeat the process using the constant voltage drop model with \(V_{\text{on}} = 0.65\) V. #### *Circuit Descriptions:* - **Figure P3.66a:** - Circuit includes a 5V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is at -5V. - **Figure P3.66b:** - Circuit includes a 3V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is grounded (0V), and the other connection is at -7V. - **Figure P3.66c:** - Circuit contains a 7V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is at -3V. - **Figure P3.66d:** - Circuit includes a 5V voltage source, a 16 kΩ resistor, and a diode in series. - The lower node is at -5V. #### Analysis Approach: 1. **Ideal Diode Model:** - Assume the diode acts as a short circuit when ON and an open circuit when OFF. - Analyze resulting circuit conditions for current (\(I\)) and voltage (\(V\)) across components. 2. **Constant Voltage Drop Model:** - The diode turns ON with a forward voltage drop of 0.65V. - Determine current (\(I\)) and voltage (\(V\)) considering this voltage drop. #### Conclusion:
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