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3. Using Kirchoff's laws calculate the current passing through each branch in Figure 3 as a function of the fixed resistor values, R if the potentiometer is set at 5 kn. Calculate the voltage drop across RL. Show your calculations. Hint: Split the potentiometer into two 5 k resistors. d.c. power supply + Boxed components I 1ΚΩ 10kΩ potentiometer R R₁ 1ΚΩ V₁ ~ 10 V d.c. Figure 3: Potential divider circuit using the 10 k potentiometer on the right-hand side of the box.

3. Using Kirchoff's laws calculate the current passing through each branch in Figure 3 as a function of the fixed resistor values, R if the potentiometer is set at 5 kn. Calculate the voltage drop across RL. Show your calculations. Hint: Split the potentiometer into two 5 k resistors. d.c. power supply + Boxed components I 1ΚΩ 10kΩ potentiometer R R₁ 1ΚΩ V₁ ~ 10 V d.c. Figure 3: Potential divider circuit using the 10 k potentiometer on the right-hand side of the box.

Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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3. Using Kirchoff's laws calculate the current passing through each branch in Figure 3 as a function of the fixed resistor values, R if the potentiometer is set at 5 kn. Calculate the voltage drop across RL. Show your calculations. Hint: Split the potentiometer into two 5 k resistors. d.c. power supply + Boxed components I 1ΚΩ 10kΩ potentiometer R R₁ 1ΚΩ V₁ ~ 10 V d.c. Figure 3: Potential divider circuit using the 10 k potentiometer on the right-hand side of the box.
Transcribed Image Text:3. Using Kirchoff's laws calculate the current passing through each branch in Figure 3 as a function of the fixed resistor values, R if the potentiometer is set at 5 kn. Calculate the voltage drop across RL. Show your calculations. Hint: Split the potentiometer into two 5 k resistors. d.c. power supply + Boxed components I 1ΚΩ 10kΩ potentiometer R R₁ 1ΚΩ V₁ ~ 10 V d.c. Figure 3: Potential divider circuit using the 10 k potentiometer on the right-hand side of the box.
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