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- כטן ε БӘЛ (b) Adsorption of a solute can take place from the liquid surface to a solid surface when the solution is treated with a solid. Assuming that the solute adsorbs strongly compared to the solvent, sketch comparative qualitative plots of x/m (amount adsorbed /g) vs C (concentration in solution) for the individual adsorption of ethyl, n- propyl and n-butyl alcohols from an aqueous solution to a hydrophilic silica sample. Give suitable explanation for the plots. (2)6. A dilute silver nitrate solution is added to a slight excess iodide solution. A solution of AgI is face adsorbs.chemohollic.com formed whose surface adsorbs. (a) I (b) NO3 + (c) Nat (d) Ag*A + B = A-B The formation of non-covalent complexes in water is a fundamental reaction in bioorganic chemistry. For reactions where A or B (or both) are proteins, kon is often in the neighborhood of 1.00 x 10° M-'s-1 (an approximate value for the diffusion limit). Using this value of kon, determine the half-life in seconds of the following common biochemical complexes (A-B) obtained from an antibody which binds a viral protein with Ka = 5.00 × 10-7 M. t12 =
- answer it please no rounding off until it reached the answers.What is the difference between a diffusion reaction and a diffusion-controlled reaction?The following data were obtained for the adsorption of acetone on charcoal from an aqueous solution at 180C. Y (millimoles/g) C (millimoles/liter) 0.208 2.34 0.618 14.65 1.075 41.03 1.5 88.62 2.08 177.69 2.88 268.97 a) Find the constants k and n of the Freundlich equation. b) Find the constants a and b in the Langmuir equation. c) Find the constants k and n in the Temkin isotherm. d) Which of the isotherm fit the data best? Answer letter D only thank you!
- For the adsorption of a substance A from aqueous solution by charcoal at 25C, the Freundlich constants are n = 3.0 and k = 0.50 for y in grams per gram and C in g L-1. What weight of A will be adsorbed by 2 g of charcoal from 1 L of a solution containing originally 2 g of substance? Answer is [1 g]2. a) Calculate the hard-sphere (HS) collision theory rate constant ks for the reaction NO(g) + C₁₂(g) Þ NOCl(g) + HS Cl(g) at 300 K in units of dm³ mols. The collision diameters of NO and Cl₂ are 370 and 540 pm, respectively. 16.0 g/mol, and mcı Use masses of m₁ = 14.0 g/mol, mo = 35.0 g/mol. N = b) Now include the line-of-centers (LOC) energy criterion to find koc in units of dm³ mol¹ s¹ using E₁ = 84.9 kJ mol LOC LOC c) Calculate the ratio of kчs and kLoc to the experimental rate constant at 300 K given A = 3.981 10° dm³ mol¹ s and E₁ = 84.9 kJ mol¹. a -16
- You have a treatment process in which a microbial population consumes a substrate (chemical A) according to Monod kinetics, with Hmax=2 d', Ks = 350 mg/L, and Y 0.15 g cells/g A. What biomass concentration (in mg/L) must be maintained to result in a substrate utilization rate of -1000 mg/L- hr for a concentration of A equal to 5000 mg/L? %3D %3!The following data were obtained for the adsorption of a certain material (ORA) on activated carbon at 25 °C. Sample Activated carbon mass (g) 1.0119 [ORA) initial (M) [ORA] at equilibrium (М) 0.0044 number 0.0096 1.0186 1.0360 0.0289 0.0207 3 0.0578 0.0446 0.0721 0.1002 4 1.0129 0.0867 1.0393 0.1156 1.0312 1.0198 0.1445 0.1926 0.2407 0.2889 0.1270 7 1.0270 1.0252 0.1742 0.2227 0.1108 8 1. Try fitting these data using Langmuir Isotherm and obtain K and monolayer of ORA molecules per one gram 3. Which isotherm describe best the adsorption of ORA on activated carbon and why? 4. If a monolayer of N2 molecules is 0.03075 mole per one gram of activated carbon, and the surface area on one N2 molecules is 0.162 nm, determine: a. surface area per one gram of activated carbon b. surface area of one ORA moleculeno rounding off