3. †(n) = 6+ (n-1) + 4+ (n-2)+4(3")
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solve recursion
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- sum= 0; for (int i = 0; i 1) { sum++; i= 1/2; } = 2*log2 (n) We denote by Ta(n), Tb (n), Te(n) the running time of the three fragments. 1. Give evaluations for Ta(n), Tb (n), Te(n). 2. Is T(n) = O(Ta(n)) ? Answer YES or NO and justify your answer. 3. Is Te(n) = (Ta(n)) ? Answer YES or NO and justify your answer.multiplier 3 make_multiplier (3) print (multiplier_2(5)) # Output: 10 print (multiplier_3(5)) 10 15 In [4]: def sum_of_digits (n): if n < 10: else: return n I return n % 10 + sum_of_digits (n // 10) # Example usage: result sum_of_digits (123456222) print("Sum of digits:", result) # Output: 10 In []: Sum of digits: 27 How did it become 27 I want to explain in detail and give different examples to understand the materialCFG: Example 1 • Draw the CFG for the following code: int f(int n){ } int m = n* n; if (n < 0) else return 0; return m;
- the only method you are alowed to use is substitution method, a)t(n)=7t(n/8) + 2n is O(n) b)t(n)=t(n-1) + 8n is 0(n^2)Given the following pseudocode: function fun2(n) { var outer_count = 0; var inner_count %3D for (i=0; i 0, as an expression of normal arithmetic and n, what is the value of outer_count that counts the number of times the outer loop executes? Enter an expression Fun.2.inner: Assuming n E N and n > 0, as an expression of normal arithmetic and n, what is the value of inner_count that counts the number of times the inner loop executes? Enter an expressionO(log n) + O(n) = ?
- 4. A={3,4}, B={4,5}. An B= AUB= A-B= A OB= AXB=Answer in JavaScript Tim while preparing for his CAT exam, was studying the topic Number Systems. He encountered a loving da question: Given a number N, find the number of pairs (cy) where both x and y are less than N and Highent Common Factor(HCF) of x and y is 1. You have to solve the question for him. Note: 0 can be included within the pairs Input Specification: Input: The number N from which the pairs (x,y) should be obtained Output Specification: Return the total number of pairs Example 1: input1: 4 Output: 9 Explanation: The pairs can be (1,0) ,(0,1) (1,1) (1,2) (2,1) (0, 3) (3,1) (2,3) (0,2) So, a total of 9 pairsnbm.m//,//
