3. Draw the structure of each compound named below. A: pentane HOW 190 1 1703 901 rizzszib yd lonxudobayo bas B: 2,2-dimethylpropane 1616092 100y 10 2290svinetts bri 22922A d berimistab el zolamsz 9allitalb bet boy lo vihue bas (sigoy no nwone 26) onuragmas been si arluas (stnemingqxs nuoy rigurds low abrow 19rito nl (21291 quong Isnotsnut sinago sn baballos E siomsz ross nerw smulov stal Jab smulov 16:31 16 bevisado enototaqmst basrl-life noitalidzib end to bas bris 112 eri: 15en bezellos alqmse tellalb si to ug D: 2,3,4-trimethylpentane C: octane E: decane am 06910 F: 2,2,5,5-tetramethylhexane DES 29msn JAYUI 2601 WORSH 4 D

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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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3. Draw the structure of each compound named below.
A: pentane
B: 2,2-dimethylpropane
yo lonxudolaya bns
OST
d berlim 1919h al zalomsz rallijalb betello by to vihuco bus (qsg y no wone 2)
C: octane
E: decane
anoliasu notezuzzio
ass bez ot
juoy to 225m9vibbetts brii 22922A
arluas (stneminsqxs nuoy rigurat low abrow 19rito al (21291 quong Isnoitinut inspio s
batallod Ew siomsz ross nertw smulov straib
smulov 161 16 bevisado mutotaqmst bssd-life
noitalidzib ent to bas bris tot2 ari: 159n berbellos alorse tellitalb ar to viniq
menmated soch tod
D: 2,3,4-trimethylpentane
F: 2,2,5,5-tetramethylhexane
să 971 092210210 2prvomos into an to 1 in gallion ons asmsn JAYUI 260 wO190 91062 981 S
This plot of molar mass vs. temperature shows a single data wed 150 lifelb ismoitosti bns siqmiz no osbiv ymabso
point - the boiling point of pentane (molecule A) is 36 °C.subslom sitt svitosts to says srit ritiw equong nalogno
Using the labels of the other molecules you drew above (B, C,
a2=tniog gnillod (sncnsqoig-S) anoisos
D, E and F), ADD DATA POINTS to the plot to indicate
approximately where you'd expect the boiling point of each
compound to be located relative to that of pentane.
Explain your predictions as completely as you can, in terms of
the relative masses and intermolecular interactions of these
molecules. branching
because serface area) smaller
50
Boiling Point, °C
-50
50
A•
Molar Mass, g/mol
100
150
@
lubelom does 10 25226m bis 2010 v1116 end to emmat ni znaoamas szert to pin
200
Transcribed Image Text:3. Draw the structure of each compound named below. A: pentane B: 2,2-dimethylpropane yo lonxudolaya bns OST d berlim 1919h al zalomsz rallijalb betello by to vihuco bus (qsg y no wone 2) C: octane E: decane anoliasu notezuzzio ass bez ot juoy to 225m9vibbetts brii 22922A arluas (stneminsqxs nuoy rigurat low abrow 19rito al (21291 quong Isnoitinut inspio s batallod Ew siomsz ross nertw smulov straib smulov 161 16 bevisado mutotaqmst bssd-life noitalidzib ent to bas bris tot2 ari: 159n berbellos alorse tellitalb ar to viniq menmated soch tod D: 2,3,4-trimethylpentane F: 2,2,5,5-tetramethylhexane să 971 092210210 2prvomos into an to 1 in gallion ons asmsn JAYUI 260 wO190 91062 981 S This plot of molar mass vs. temperature shows a single data wed 150 lifelb ismoitosti bns siqmiz no osbiv ymabso point - the boiling point of pentane (molecule A) is 36 °C.subslom sitt svitosts to says srit ritiw equong nalogno Using the labels of the other molecules you drew above (B, C, a2=tniog gnillod (sncnsqoig-S) anoisos D, E and F), ADD DATA POINTS to the plot to indicate approximately where you'd expect the boiling point of each compound to be located relative to that of pentane. Explain your predictions as completely as you can, in terms of the relative masses and intermolecular interactions of these molecules. branching because serface area) smaller 50 Boiling Point, °C -50 50 A• Molar Mass, g/mol 100 150 @ lubelom does 10 25226m bis 2010 v1116 end to emmat ni znaoamas szert to pin 200
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