3. Calculate AS at 25°C and 1 atm pressure in J/(mol-K) for the following reaction CH4(8) + N₂(g) + 164 kJ → HCN(8) + NH3(8) AG° = 159 kJ. [a] 1x10² [b] 2 [c] 4x10² [d] 2x10¹ [e] 7x10¹
3. Calculate AS at 25°C and 1 atm pressure in J/(mol-K) for the following reaction CH4(8) + N₂(g) + 164 kJ → HCN(8) + NH3(8) AG° = 159 kJ. [a] 1x10² [b] 2 [c] 4x10² [d] 2x10¹ [e] 7x10¹
Chemistry: Principles and Practice
3rd Edition
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Chapter17: Chemcial Thermodynamics
Section: Chapter Questions
Problem 17.38QE
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![3. Calculate AS at 25°C and 1 atm pressure in J/(mol-K) for the following
reaction
CH4(8) + N₂(g) + 164 kJ → HCN(g) + NH3(8)
AG° = 159 kJ.
[a] 1x10²
[b] 2
[c] 4x10²
[d] 2x10¹
[e] 7x10¹](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F832e79fc-6158-419d-bfc3-1c34737913d5%2Ff8f31dd7-d920-49be-b855-7cc19f2d3946%2F2a0qmcm_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3. Calculate AS at 25°C and 1 atm pressure in J/(mol-K) for the following
reaction
CH4(8) + N₂(g) + 164 kJ → HCN(g) + NH3(8)
AG° = 159 kJ.
[a] 1x10²
[b] 2
[c] 4x10²
[d] 2x10¹
[e] 7x10¹
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