8. Determine the value of AH° for the following reaction: 2 CO(g) + O2(g) → 2 CO2(g) Substance AH°f (kJ/mol) CO(g) CO₂(g) a)-283.2 b)-504.2 c)-566.4 d) -1008.4 e) Not enough information provided. -110.5 -393.7
8. Determine the value of AH° for the following reaction: 2 CO(g) + O2(g) → 2 CO2(g) Substance AH°f (kJ/mol) CO(g) CO₂(g) a)-283.2 b)-504.2 c)-566.4 d) -1008.4 e) Not enough information provided. -110.5 -393.7
Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
Determine the value of ΔH° for the following reaction:
\[ 2 \text{CO}(g) + \text{O}_2(g) \rightarrow 2 \text{CO}_2(g) \]
**Data Provided:**
| Substance | ΔH°f (kJ/mol) |
|-----------|---------------|
| CO(g) | -110.5 |
| CO2(g) | -393.7 |
**Options:**
a) -283.2
b) -504.2
c) -566.4
d) -1008.4
e) Not enough information provided.
**Explanation:**
To calculate the standard enthalpy change (ΔH°) for the reaction, use the formula:
\[ \Delta H^\circ = \sum \Delta H^\circ_f \text{ (products)} - \sum \Delta H^\circ_f \text{ (reactants)} \]
Calculate:
\[ \Delta H^\circ = [2 \times (-393.7)] - [2 \times (-110.5)] \]
\[ \Delta H^\circ = (-787.4) - (-221.0) \]
\[ \Delta H^\circ = -787.4 + 221.0 \]
\[ \Delta H^\circ = -566.4 \]
Thus, the correct option is c) -566.4.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ffddc283e-bfa7-4492-b564-1add28da6d82%2F5a9ba6d2-1a90-4831-887e-a7ed4783d617%2Fe0sshue_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
Determine the value of ΔH° for the following reaction:
\[ 2 \text{CO}(g) + \text{O}_2(g) \rightarrow 2 \text{CO}_2(g) \]
**Data Provided:**
| Substance | ΔH°f (kJ/mol) |
|-----------|---------------|
| CO(g) | -110.5 |
| CO2(g) | -393.7 |
**Options:**
a) -283.2
b) -504.2
c) -566.4
d) -1008.4
e) Not enough information provided.
**Explanation:**
To calculate the standard enthalpy change (ΔH°) for the reaction, use the formula:
\[ \Delta H^\circ = \sum \Delta H^\circ_f \text{ (products)} - \sum \Delta H^\circ_f \text{ (reactants)} \]
Calculate:
\[ \Delta H^\circ = [2 \times (-393.7)] - [2 \times (-110.5)] \]
\[ \Delta H^\circ = (-787.4) - (-221.0) \]
\[ \Delta H^\circ = -787.4 + 221.0 \]
\[ \Delta H^\circ = -566.4 \]
Thus, the correct option is c) -566.4.
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