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3. A survey of 1,700 licensed drivers revealed that 33% have received at least 1 speeding ticket in the last 2 years. Construct a 99% confidence interval for the population mean of drivers that have received at least 1 speeding ticket in the last 2 years. OCI = (30.76%, 35.24%) CI = (31.12%, 34.88%) CI = (30.06%, 35.94%) %3D O CI = (31.67%, 34.23%)

3. A survey of 1,700 licensed drivers revealed that 33% have received at least 1 speeding ticket in the last 2 years. Construct a 99% confidence interval for the population mean of drivers that have received at least 1 speeding ticket in the last 2 years. OCI = (30.76%, 35.24%) CI = (31.12%, 34.88%) CI = (30.06%, 35.94%) %3D O CI = (31.67%, 34.23%)

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
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3. A survey of 1,700 licensed drivers revealed that 33% have received at least 1 speeding ticket in the last 2 years. Construct a 99% confidence interval for the population mean of drivers that have received at least 1 speeding ticket in the last 2 years. CI = (30.76%, 35.24%) O CI = (31.12%, 34.88%) %3D CI = (30.06%, 35.94%) %3D CI = (31.67%, 34.23%)
Transcribed Image Text:3. A survey of 1,700 licensed drivers revealed that 33% have received at least 1 speeding ticket in the last 2 years. Construct a 99% confidence interval for the population mean of drivers that have received at least 1 speeding ticket in the last 2 years. CI = (30.76%, 35.24%) O CI = (31.12%, 34.88%) %3D CI = (30.06%, 35.94%) %3D CI = (31.67%, 34.23%)
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Step 1

Note: Since the proportion of the people is given, therefore, the confidence interval will be made for proportions.

Given:

The number of people surveyed are n=1700.

The proportion of people who have received at least 1 speeding ticket in the last 2 years is p^=0.33.

The confidence interval (C.I) for the proportion of people who have received at least 1 speeding ticket in the last 2 years is given as:

                                                                C.I=p^±zα2p^(1-p^)n

The level of confidence is 99%, which implies:

The level of significance is:

                                        α=1-0.99  =0.01

 

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