3. A steel bolt through a 25-in long aluminum tube has the nut turned on until it just touches the end of the tube. No stress is introduced on the bolt or the tube. The temperature of the assembly is raised from 70 to 79 degrees Fahrenheit. The cross- sectional area of the bolt is O.08 sq. inch and the cross-sectional area of the tube of 0.25 sq. inch. For steel: E = 30 x 10^6 psi, coefficient of thermal expansion = 6.5 x 10^-6 %3D per degree Fahrenheit. For aluminum: E = 10 x 10^6 psi, coefficient of thermal expansion = 13.0 x 10^-6 per degree Fahrenheit. Find the thermal deformation (in inches) of the steel bolt. (Write your answer to 6- decimal places. ) * Your answer Find the thermal deformation (in inches) of the aluminum tube. (Write your answer to 6- decimal places.) *

Elements Of Electromagnetics
7th Edition
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Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
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3. A steel bolt through a 25-in long aluminum
tube has the nut turned on until it just
touches the end of the tube. No stress is
introduced on the bolt or the tube. The
temperature of the assembly is raised from
70 to 79 degrees Fahrenheit. The cross-
sectional area of the bolt is 0.08 sq. inch and
the cross-sectional area of the tube of 0.25
sq. inch. For steel: E = 30 x 10^6 psi,
coefficient of thermal expansion = 6.5 x 10^-6
per degree Fahrenheit. For aluminum: E = 10 x
10^6 psi, coefficient of thermal expansion =
13.0 x 10^-6 per degree Fahrenheit.
Find the thermal deformation (in inches) of
the steel bolt. (Write your answer to 6-
decimal places. ) *
Your answer
Find the thermal deformation (in inches) of
the aluminum tube. (Write your answer to 6-
decimal places.) *
Your answer
Find the stress (in psi) induced in the steel
Transcribed Image Text:3. A steel bolt through a 25-in long aluminum tube has the nut turned on until it just touches the end of the tube. No stress is introduced on the bolt or the tube. The temperature of the assembly is raised from 70 to 79 degrees Fahrenheit. The cross- sectional area of the bolt is 0.08 sq. inch and the cross-sectional area of the tube of 0.25 sq. inch. For steel: E = 30 x 10^6 psi, coefficient of thermal expansion = 6.5 x 10^-6 per degree Fahrenheit. For aluminum: E = 10 x 10^6 psi, coefficient of thermal expansion = 13.0 x 10^-6 per degree Fahrenheit. Find the thermal deformation (in inches) of the steel bolt. (Write your answer to 6- decimal places. ) * Your answer Find the thermal deformation (in inches) of the aluminum tube. (Write your answer to 6- decimal places.) * Your answer Find the stress (in psi) induced in the steel
O 02:57:54
10^6 psi, coefficient of thermal expansion =
%3D
13.0 x 10^-6 per degree Fahrenheit.
Find the thermal deformation (in inches) of
the steel bolt. (Write your answer to 6-
decimal places. )
Your answer
Find the thermal deformation (in inches) of
the aluminum tube. (Write your answer to 6-
decimal places.) *
Your answer
Find the stress (in psi) induced in the steel
bolt by the temperature change. *
Your answer
Find the stress (in psi) induced in the
aluminum tube by the temperature change. *
Your answer
Transcribed Image Text:O 02:57:54 10^6 psi, coefficient of thermal expansion = %3D 13.0 x 10^-6 per degree Fahrenheit. Find the thermal deformation (in inches) of the steel bolt. (Write your answer to 6- decimal places. ) Your answer Find the thermal deformation (in inches) of the aluminum tube. (Write your answer to 6- decimal places.) * Your answer Find the stress (in psi) induced in the steel bolt by the temperature change. * Your answer Find the stress (in psi) induced in the aluminum tube by the temperature change. * Your answer
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