3. A soil sample having no particles larger than No. 4 sieve is classified as a sandysilt, ML, by the Unified Soil Classification System (LL = 25 %, PL = 5 %; silt particlescomprise 70 % of the sample, sand 15 %, and clay 15 %). What is the probablesoil classification in the AASHTO system? In the US Dept. of Agriculture texturalsystem?

Sandy Silt ML LL=25% PL=5% Slit=70% Sand=15% Clay=15% From Uscs classification, we can evaluate that…

Answered: 3. A soil sample having no particles…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Given the test results that follow, classify the soil in both the Unified Soil Classification System (USCS) and the AASHTO system.
Question 1 Classify the following soil using the U.S. Department of Agriculture textural classification chart. Sand - 50 Silt - 15 Clay - 35 A) sandy clay В loam clay loam D sandy clay loam
Classify soils A, B, C, and D based on the USCS (ASTM D2487 – 17) indicating the symbol and soil description. Additionally, classify the soils according to the AASHTO Soil Classification System indicating the name of the soil group as well as the GI. Sieve Opening (mm) Percent Passing (%) Soil D Soil C Sieve Number Soil A Soil B No. 4 4.750 78 75 60 78 88 88 No. 10 2.000 75 75 75 No. 18 1.000 60 60 60 No. 30 0.600 45 45 45 45 No. 40 0.425 30 30 30 30 No. 60 0.250 22 22 22 22 No. 100 0.150 15 15 15 15 No. 140 0.105 10 10 10 14 No. 200 0.075 8. 4 13 LL 60 60 20 20 PL 25 35 14 14
SITUATION 9 The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
4. Classify the following soil by the Unified Soil Classification System: Percent passing No.4 sieve = 82 Percent passing No.10 sieve = 71 Percent passing No.40 sieve = 64 Percent passing No. 200 sieve = 41 Plasticity index = 12 Liquid limit = 31
7. Classify the following soils according to the AASHTO Soil Classification with Group Index (GI) Soil A B No. 4 95 100 Percent passing U.S. sieve No. 10 No. 20 No. 40 No. 60 No. 100 No. 200 86 65 52 46 38 25 98 95 88 82 75 65 LL PL 38 65 22 58
Classify the following soils by the Unified soil classification system. Give the group na soil Soil 1 2 Sieve analysis (percentage finer) Liquid Plastic No. 4 No. 200 limit limit 98 28.5 33.2 22.6 95 10 30 22 D10 D30 8 D60 0.085 0.12 0.135 Q1)
Classify the following soil by the Unified Soil Classification System. Percent passing No. 4 sieve = 82Percent passing No. 10 sieve = 71Percent passing No. 40 sieve = 64Percent passing No. 200 sieve = 41Liquid limit = 31Plasticity index = 12
The result of sieve analysis of three soils is given next. It is required to classify these soils according to the AASHTO Classification System. Use the attached AASHTO Classification of Highway Subgrade Materials Table. (a) Classification of Soil A. (b) Classification of Soil B. (c) Classification of Soil C. Sieve Analysis Results for Situation 9 Sieve Analysis Sieve Diameter, Percent Passing Number mm. 4.76 90 100 100 8. 2.38 84 90 100 10 2. 72 77 98 20 0.84 66 59 91 40 0.42 58 50 85 60 0.25 50 42 79 100 0.149 44 36 70 200 0.074 38 33 LL 42 46 47 PL 23 29 24 63
A soil sample has the following size distribution; 4 to 2mm = 17%, 2 to 0.05 mm = 12%, 0.5 to 0.005 mm = 22% 0.005 to 0.002 mm = 10% <0.002 mm = 39% what is the percent clay silt and sand? What are the modifier and textural classification?
For a soil specimen, given the following: % passing sieve #4-92 %, sieve #10 -81%, sieve # 40-78%, LL-48%, PL-16%, GI-18.2 classify the soil by AASHTO classification system. GI = (F200-35)[0.2 + 0.005 (LL - 40)] +0.01 (F20015)(PI – 10)
• Particle size analyses were carried out on two soils-Soil A and Soil B-and the particle size distribution curves are shown in Figure % Finer Clay 100 90 80 70 60 50 40 30 20 10 0 0.001 + Silt Soil A Sand Soil B 0.01 0.1 1 Particle size (mm) - log scale Gravel 10 Soil A B 1. Classify these soils according to USCS and ASTM-CS 2. Is either of the soils organic? LL 26 (oven-dried; assume same for not dried) Nonplastic PL 18

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