3.9.10.The centrifugal tension in belts(a) increases power transmitted(b) decreases power transmitted(c) have no effect on the power transmitted(d) increases power transmitted upto a certain speed and then decreasesWhen the belt is stationary, it is subjected to some tension, known as initial tension. The value of thistension is equal to the(a) tension in the tight side of the belt(b) tension in the slack side of the belt(c) sum of the tensions in the tight side and slack side of the belt(d) average tension of the tight side and slack side of the beltThe relation between the pitch of the chain (p) and pitch circle diameter of the sprocket (d) is given by60°(a) p=d sin(c) p=d sin(120°Twhere T Number of teeth on the sprocket.90°(b) p=d sinT180°(d) p=d sinT

9. Correct Answer: (d) average tension of the tight side and slack side of the beltExplanation:The…

Answered: 3. 9. 10. The centrifugal tension in…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

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5. Arough rule for leather belt is that effective tension in it, shall not exceed 15 N/mm of width for a belt of 10 mm thickness. This rule is applied to determine width of belt required to transmit 37 kW, under the following conditions : Angle of lap = 165°; Coefficient of friction = 0.3; Velocity of belt = 1500 m/min; Density of leather = 950 kg/m³. Find the width of belt required. Assuming limiting friction between belt and pulley rim, find the stress in the belt. [Ans. 140 mm ; 1.48 MPa]
8 An inextensible massless string goes over a frictionless pulley. Two weights of 100 N and 200 N are attached to the two ends of the string. The weights are released from rest, and start 200 N moving due to gravity. The tension in the string (in N) 100 N is
4) This Atwood's machine includes two blocks connected by a cable, going over a pulley without slipping. Block 1 (30.0 kg) is connected to a spring (70.0 N/m), and slides on a horizontal surface with a coefficient of kinetic friction of 0.0100. Block 2 is 50.0 kg, and hangs vertically from the cable. The pulley is a disk with a radius of 0.500 m, and its moment of inertia about the center of mass is 10. 0 kg-m“. a) Draw the three free body diagrams, and write out Newton's 2nd Law for each. b) Derive the equation of motion (inhomogeneous 2nd order ODE) for this system. c) Use u-substitution to rewrite this as a homogeneous 2nd order ODE. d) Assume the position x as a function of time t is of the form x(t) = A cos (wt + p) I disk for undamped natural frequency w, phase angle P, and amplitude A. The initial conditions are: x(0) v(0) = -3. 00 m/s. Solve for the position of the mass as a function of time (you need to solve for w, 4, and A). = 2. 00 m and Mz
Q2. A pulley is driven by a flat belt running at a speed of 600 m/min. The coefficient of friction between the pulley and the belt is 0.3 and the angle of lap is 160°. If the maximum tension in the belt is 700 N; find the power transmitted by a belt..
Q2 / A belt drive consist of two V- belts in parallel, on grooved pulleys of the same size. The angle of the groove is 30. The cross - section area of each belt is 750 mm and u is 0.12. The density of the belt material is 1.2 Mg/m and the maximum safe stress in the material is 7 MN/m. Answer the following questions 1- The centrifugal tension in belts is . (a) increases power transmitted (b) decreases power transmitted (c) have no effect on power transmitted (d) increases power transmitted up to a certain speed and then decreases 2- The power that can be transmitted between pulleys of 300 mm diameter rotating at 1500 r.p.m is .. 3- The shaft speed in r.p.m at which the power transmitted would be a maximum 4- When two pulleys are connected by means of an open belt drive, then both the pulleys will rotate is opposite directions. (true or falls) 5- The length of V- belt drive are usually used for .. (a) long drives (b) short drives (c) long and short drives (d) none of these.
As speed as possible please
Power is transmitted between two shafts by a V-belt whose mass is 0.9 kg/m length. The maximum permissible tension in the belt is limited to 2.2 kN. The angle of lap is 170° and the groove angle 45°. If the coefficient of friction between the belt and pulleys is 0.17, find : 1. velocity of the belt for maximum power ; and 2. power transmitted at this velocity. [Ans. 28.54 m/s ; 30.7 kW]
Q3) A compressor, requiring 90 kW is to run at about 250 r.p.m. The drive is by V-belts from an electric motor running at 750 r.p.m. The diameter of the pulley on the compressor shaft must not be greater than 1 meter while the centre distance between the pulleys is limited to 1.75 meter. The belt speed should not exceed 1600 m/mi. Determine the number of V-belts required to transmit the power if each belt has a cross-sectional area of 375 mm² density 1000 kg/m and an allowable tensile stress of 2,5 MPa. The groove angle of the pulley is 35°. The coefficient of friction between the belt and the pulley is 0.25.
4. At the bottom of an incline at 45° to the horizontal, a 0.170 kg box is forced against a spring with constant 1500 N/m until the spring has been compressed by 0.11 m. How far does the box move up the incline before coming to rest if a) the incline is frictionless? b) there is a coefficient of kinetic friction of 0.3?
A flat belt type is used for a belt drive system connecting two pulleys 1.2m apart. The driver pulley with diameter 40 cm is rotating with the speed 350 rpm, while diameter of driven pulley is 100 cm. Coefficient of friction of the contact surface between belt and pulley is 0.3.Maximum allowable tension is 600N. (i) Find the power transmitted by the belt, P. (ii) Determine the Initial tension of the belt, TA. iii) If the flat belt is now replaced by a Vee-belt with groove angle of B = 300 , find the power transmitted by this belt. Give explanation why power transmitted by flat andVee-belt type are not the same. Explain your answer according to basic friction concept. iv) If a Vee-belt with groove angle of B = 900 is being used, find the power transmittedby this belt. Discuss your findings by comparing with answer in (i) and answer in (iii) above. (v) List and explain TWO (2) practical applications each for flat belt and Vee-belt drive
1. A pulley is driven by a flat belt running at a speed of 600 m/min. The coefficient of friction between the pulley and the belt is 0.3 and the angle of lap is 160°. If the maximum tension in the belt is 700 N ; find the power transmitted by a belt. Answer. 3.983 kW
2. Two blocks connected by a string passing over a pulley are on ramps inclined at 32 degrees and 25 degrees. The mass of block #1 is 1.8 kg and the mass of block #2 is 1.0 kg. Between block #1 and its ramp, the coefficients of static and kinetic friction are 0.15 and 0.10, respectively. There is no friction between block #2 and its ramp. The system is released from rest and the blocks move. The pulley is massless and frictionless, so you can ignore the pulley. b. C. d. 32° 25° Draw a free body diagram (FBD) for each block. Include all of the forces acting on the two blocks. Apply Newton's Second Law to each block to obtain an equation for the forces acting on each block in the x-direction and an equation for the forces acting on each block in the y-direction. Consider the information provided about this system. When the blocks are released from rest, what direction will the blocks move? Explain why? Calculate the acceleration of the blocks. I

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