The end of the boom O in Fig. 2-19a is subjected to the three concurrentand coplanar forces. Determine the magnitude and direction of theresultant force.F₂-250 NF:-200 N45°IOF-400 N(a)

Given: To solve for the resultant, we will just add all the applied forces.For the horizontal…

Answered: The end of the boom O in Fig. 2-19a is…

International Edition---engineering Mechanics: Statics, 4th Edition

4th Edition

ISBN:9781305501607

Author:Andrew Pytel And Jaan Kiusalaas

Publisher:Andrew Pytel And Jaan Kiusalaas

Chapter6: Beams And Cables

Section: Chapter Questions

Problem 6.4P: Find the internal force systems acting on sections 1 and 2.

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Repeat Prob. 4.152 assuming that the 400-kN force is applied at O instead of L.
Example The link in Fig. 2-19a is subjected to two forces F, and F2. Determine the magnitude and direction of the resultant force. F2 = 400 N F = 600 N F2 = 400 N 45% F = 600 N 45° 30° 30 xX- (a) y (b)
It is required that the resultant force acting on the eyebolt in Fig. 2-14a be directed along the positive x axis and that F, have a minimum magnitude. Determine this magnitude, the angle 0,and the corresponding resultant force. F= 0N F= s00 N F= N00 N FR 90 (c) (a)
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Answer questions 4-6:
The two tugboats apply the forces P and Q to the barge, where P = 76 kN and Q = 52 kN. [3] An additional tugboat applied a T = 102 kN (directed 26 degrees east of north) to the barge, find thedirection of the resultant force from the vertical. (Use original values for P and Q) (Answer: 22.764 kN)
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The wheels, axle, and handles of a wheelbarrow weigh W = 55 N. The load chamber and its contents weigh WL = 623 N. The drawing shows these two forces in two different wheelbarrow designs. To support the wheelbarrow in equilibrium, the man’s hands apply a force to the handles that is directed vertically upward. Consider a rotational axis at the point where the tire contacts the ground, directed perpendicular to the plane of the paper. Find the magnitude of the man’s force for both designs.
F₁ Him - F2 | m F₁ + ן F3 -1 m-
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Q1/ It is required that the resultant force acting on the eyebolt in Fig. 6 points below be directed along the positive x axis and that F2 have a minimum magnitude. Determine this magnitude, the angle e and the corresponding resultant force F:=700 N F2 e=30, FR=400 N, F2=450 N e=45, FR=300N, F2=200N e=60, FR=600N,F2=250 N e=90,FR=350N, F2=606 N Other:
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