3) Suppose we have a computer that uses a memory address word size of 8 bits. This computer has a 16-byte cache with 4 bytes per block. The computer accesses a number of memory locations throughoutthe course of running a program. Suppose this computer uses direct-mapped cache. The format of amemory address as seen by the cache is shown below:Tag4 bitsBlock2 bitsOffset2 bitsThe system accesses memory addresses in this exact order: 0x6E, 0xB9, 0x17, 0xE0, 0x4E, 0x4F, 0x50,0x91, 0xA8, 0xA9, 0xAB, 0xAD, 0x93, and 0x94. Fill out the following tables:a)AddressHitReference orMissCommentsb) Show the final contents of cache for direct addressing:BlockCache ContentsTag(represented by address)

In computer architecture, cache memory plays a critical role in reducing the time taken to access…

Answered: 3) Suppose we have a computer that uses…

Systems Architecture

7th Edition

ISBN:9781305080195

Author:Stephen D. Burd

Publisher:Stephen D. Burd

Chapter6: System Integration And Performance

Section: Chapter Questions

Problem 22VE

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Similar questions

If a microprocessor has a cycle time of 0.5 nanoseconds, what’s the processor clock rate? If the fetch cycle is 40% of the processor cycle time, what memory access speed is required to implement load operations with zero wait states and load operations with two wait states?
LI is the fastest type of cache memory built into a computer, faster even than DDR4 SDRAM memory. True or False?
Why is binary data representation and signaling the preferred method of computer hardware implementation?
(Practice) Although the total number of bytes varies from computer to computer, memory sizes of millions and billions of bytes are common. In computer language, the letter M representsthe number 1,048,576, which is 2 raised to the 20th power, and G represents 1,073,741,824, which is 2 raised to the 30th power. Therefore, a memory size of 4 MB is really 4 times 1,048,576 (4,194,304 bytes), and a memory size of 2 GB is really 2 times 1,073,741,824 (2,147,483,648 bytes). Using this information, calculate the actual number of bytes in the following: a. A memory containing 512 MB b. A memory consisting of 512 MB words, where each word consists of 2 bytes c. A memory consisting of 512 MB words, where each word consists of 4 bytes d. A thumb drive that specifies 2 GB e. A disk that specifies 4 GB f. A disk that specifies 8 GB
Processor R is a 64-bit RISC processor with a 2 GHz clock rate. The average instruction requires one cycle to complete, assuming zero wait state memory accesses. Processor C is a CISC processor with a 1.8 GHz clock rate. The average simple instruction requires one cycle to complete, assuming zero wait state memory accesses. The average complex instruction requires two cycles to complete, assuming zero wait state memory accesses. Processor R can’t directly implement the complex processing instructions of Processor C. Executing an equivalent set of simple instructions requires an average of three cycles to complete, assuming zero wait state memory accesses. Program S contains nothing but simple instructions. Program C executes 70% simple instructions and 30% complex instructions. Which processor will execute program S more quickly? Which processor will execute program C more quickly? At what percentage of complex instructions will the performance of the two processors be equal?
_____ is a CPU design technique in which instruction execution is divided into multiple stages and different instructions can execute in different stages simultaneously.
A(n) __________ is a storage location implemented in the CPU.
Assembly (machine) language programs for most computers use __________ notation to represent memory address values.
A(n) ________________ instruction always alters the instruction execution sequence. A(n) ______________ instruction alters the instruction execution sequence only if a specified Condition is true.

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