w W 2. Consider alphabet Σ = regular. {0,1} and language L = {wer : [w; # Σ Σ (1 - w;)). Prove or disprove that L is i=1 i=1
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- w |w Consider alphabet Σ = {0,1} and language L = = {wες : Σw # i=1 i=1 regular. Σ (1 - w;)}. Prove or disprove that L isFalse For each language L over a given alphabet E, let 1(L, E) denote the language over E obtained from L by generating all permutations of its strings - that is, r(L, E) -{we E*: there is a string v in L such that w is a permutation of v ). Specify which one of the following statements is true. Choose None of the other statements is true. The language r((0b1)*, (0, b,1}) is decidable. The language n((Ob1)*, (0, b,1}) is regular. There is no regular language L over an alphabet E such that the language n(L, E) fails to be context-free. Consider alnhaber E-Lo and context-free grammar G over E with precisely oneConstruct a graphical representation of DFA that accepts L={w∈(a+b)*: na(w) is even, nb(w)>1}no need to include explanations, just the graphical DFA.Please note that “a”s don't need to be consecutive.
- Let ∑ = {a, b, #} and L = { w | w cannot be written as t#s#t with s, t ∈ {a, b}*}. Show that L is not regular.Given: Language L3 = {w ϵ {a,b}* | w starts in ab and ends in bb} Construct the DFA representing the given language L3. Assume the layout of the DFA is as follows: ->A->B->C->D->E*. That is, the number of states are five (5) and A is the starting state and E is the accepting state. How many self-loop edge/s in the constructed DFA representing the given language L3? Don't give wrong answer. Upvote for only correct one else downGiven: Language L2 = {w ϵ {a,b}* | w contains substring aab} Construct the DFA representing the given language L2. Assume the layout of the DFA is as follows: ->A->B->C->D*. That is, the number of states are four (4) and A is the starting state and D is the accepting state. How many self-loop edge/s in the constructed DFA representing the given language L2?
- Correct and detailed answer will be Upvoted else downvoted directly. Thank you!∑ = {C,A,G,T}, L = { w : w = CAjGnTmC, m = j + n }. For example, CAGTTC ∈ L; CTAGTC ∉ L because the symbols are not in the order specified by the characteristic function; CAGTT ∉ L because it does not end with C; and CAGGTTC ∉ L because the number of T's do not equal the number of A's plus the number of G's. Prove that L ∉ RLs using the RL pumping theorem.Consider the language L of strings over the alphabet Σ = {a, b} which contain an equal number of a’s and b’s, and the set of b’s is consecutive in the string, e.g., ab, abba, aabb, abbbaa, aaabbbbbaa, etc. Note that ε ∈ L for completeness (0 number of a’s is equal to 0 number of b’s, which are also consecutive). Show that this language is context-free by giving a context-free grammar.