3 ft 4 ft 8 ft 12 ft The window: A = Ix W A = 3 ft x 4 ft = 12 sq ft Heat load = Heat transfer multiplier x area Btu Btu Heat load = 70 x 12 sq ft = 840 h- sq ft The wall: A = 1 x w - area of window 12 ft x 8 ft – 12 sq ft = 96 sq ft – 12 sq ft A = A = 84 sq ft Heat load = Heat transfer multiplier x area Btu Btu x 84 sq ft = 420 Heat load = 5 h. sq ft Btu + 420 h Btu = 1,260 Btu The entire side of the house: Heat load = 840

Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question

Find the heat load for the following side of a house for a 70°F design temperature
difference. The wall is a wood frame with siding and 31⁄2 inches of insulation. The window
is double pane.

3 ft
4 ft
8 ft
12 ft
The window:
A = Ix W
A = 3 ft x 4 ft = 12 sq ft
Heat load = Heat transfer multiplier x area
Btu
Btu
Heat load = 70
x 12 sq ft = 840
h- sq ft
The wall:
A = 1 x w - area of window
12 ft x 8 ft – 12 sq ft = 96 sq ft – 12 sq ft
A =
A = 84 sq ft
Heat load = Heat transfer multiplier x area
Btu
Btu
x 84 sq ft = 420
Heat load = 5
h. sq ft
Btu
+ 420
h
Btu
= 1,260
Btu
The entire side of the house:
Heat load = 840
Transcribed Image Text:3 ft 4 ft 8 ft 12 ft The window: A = Ix W A = 3 ft x 4 ft = 12 sq ft Heat load = Heat transfer multiplier x area Btu Btu Heat load = 70 x 12 sq ft = 840 h- sq ft The wall: A = 1 x w - area of window 12 ft x 8 ft – 12 sq ft = 96 sq ft – 12 sq ft A = A = 84 sq ft Heat load = Heat transfer multiplier x area Btu Btu x 84 sq ft = 420 Heat load = 5 h. sq ft Btu + 420 h Btu = 1,260 Btu The entire side of the house: Heat load = 840
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